Answer:
![\boxed{\textsf{ The total surface area of the cuboid is \textbf{62 cm} $\sf ^2$ .}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctextsf%7B%20The%20total%20surface%20area%20of%20the%20cuboid%20is%20%5Ctextbf%7B62%20cm%7D%20%24%5Csf%20%5E2%24%20%20.%7D%7D)
Step-by-step explanation:
Given that the base area of the cuboid is 7cm² . And it's volume is 21cm³ . We need to find its total surface area . Now here we need to find the height . We can find height as ,
<u>Height</u><u> </u><u>:</u><u>-</u>
Let's find out the Total surface area .
<u>TSA </u><u>of </u><u>cuboid</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Put </u><u>on</u><u> the</u><u> respective</u><u> values</u><u> </u><u>:</u><u>-</u><u> </u>
![\sf\implies TSA_{(cuboid)}= 2( lb + bh + hl )\\\\\sf\implies TSA_{(cuboid)}= 2( 7cm\times 1cm + 1cm\times 3cm + 3cm \times 7 cm ) \\\\\sf\implies TSA_{(cuboid)}=2 ( 7cm ^2+3cm^2+21cm^2 ) \\\\\sf\implies TSA_{(cuboid)}= 2\times 31cm^2 \\\\\sf\implies \boxed{\pink{\frak{ TSA_{(cuboid)}= 62 cm^2}}}](https://tex.z-dn.net/?f=%5Csf%5Cimplies%20TSA_%7B%28cuboid%29%7D%3D%202%28%20lb%20%2B%20bh%20%2B%20hl%20%29%5C%5C%5C%5C%5Csf%5Cimplies%20TSA_%7B%28cuboid%29%7D%3D%202%28%207cm%5Ctimes%201cm%20%2B%201cm%5Ctimes%203cm%20%2B%203cm%20%5Ctimes%207%20cm%20%29%20%5C%5C%5C%5C%5Csf%5Cimplies%20TSA_%7B%28cuboid%29%7D%3D2%20%28%207cm%20%5E2%2B3cm%5E2%2B21cm%5E2%20%29%20%5C%5C%5C%5C%5Csf%5Cimplies%20TSA_%7B%28cuboid%29%7D%3D%20%202%5Ctimes%2031cm%5E2%20%5C%5C%5C%5C%5Csf%5Cimplies%20%5Cboxed%7B%5Cpink%7B%5Cfrak%7B%20TSA_%7B%28cuboid%29%7D%3D%20%2062%20cm%5E2%7D%7D%7D)
Answer:
280 yd
Step-by-step explanation:
Volume of a prism = Bh
B = 8 x 5
h = 7
8 x 5 x 7 = 280
Answer:
15 houses
Step-by-step explanation:
1/3 * 72 = 24
5/8 * 24 = 15
No because all the sides don’t add up to 90 degrees
The cosine for ∠A is
.
Option: A.
<u>Step-by-step explanation:</u>
From the given diagram,
Opposite = 8 ft.
Adjacent = 5 ft.
In trigonometry, the formula for cosine =
.
We are not given with hypotenuse. So we have to find the hypotenuse using Pythagorean Theorem ![hypotenuse = \sqrt{opposite^2+adjacent^2}](https://tex.z-dn.net/?f=hypotenuse%20%3D%20%5Csqrt%7Bopposite%5E2%2Badjacent%5E2%7D)
.
.
hypotenuse =
.
cosine =
.
Multiply
in both numerator and denominator,
The cosine for ∠A is
.