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konstantin123 [22]
3 years ago
15

Carl wants to buy a television that cost $500 including taxes. to pay for television he will use a payment plan that requires hi

m to make a down payment of $125 and then pay $70.50 each month for six months what is the percent increase from the original cast of the television to the cost of the television using a payment plan.
Mathematics
1 answer:
NISA [10]3 years ago
8 0

Answer:

12 %

Step-by-step explanation:


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What is the respond for 4(b-6)+19
vlabodo [156]
So I think you’re asking for the solution to the equation mentioned.

The answer would be 4b-5

Explanation:
Steps:

4(b-6)+19

4b-24+19

4b-5 (Answer)


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Find square root of 82369 by division method step by step​
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Answer:

I think this ans may help you

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What are the zeros of this function? <br>look at graph<br>a.<br>b.<br>c.<br>d.
fredd [130]
The zeros of the function occur when the graph meet the x-axis so in this case the zeros occur at B ( 0 and 5)
4 0
2 years ago
Mattie’s house consist of two stories and an attic.the first floor is 8 5/6 feet tall the second floor is 7 1/2 feet tall and th
Trava [24]

Answer:

The attic is  

7

feet tall

Step-by-step explanation:

a=73/3-53/6-17/2

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8 0
2 years ago
Read 2 more answers
A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.
Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

t=\sqrt{\frac{2h}{a}} ,where h=height of release

a=acceleration

a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}

Where I=moment of inertia

a for hoop

a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}

a=\frac{g\sin \theta }{2}

a for Uniform solid cylinder

a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}

a=\frac{2g\sin \theta }{3}

a for spherical shell

a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}

a=\frac{3g\sin \theta }{5}

a for Uniform Solid

a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}

a=\frac{5g\sin \theta }{7}

time taken will be inversely proportional to the square root of acceleration

t_1=k\sqrt{2}=1.414k

t_2=k\sqrt{\frac{3}{2}}=1.224k

t_3=k\sqrt{\frac{5}{3}}=1.2909k

t_4=k\sqrt{\frac{7}{5}}=1.183k

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0
3 years ago
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