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professor190 [17]
4 years ago
5

What is the prime factorization of 1,260?

Mathematics
1 answer:
maks197457 [2]4 years ago
3 0
A. 2*2*3*3*5*7

Whilst B and C both also yield 1,260, they aren't broken down in to their prime factors. In B, 4 can be broken down in to 2*2 and 9 in to 3*3, and in C, 6 can be broken down in to 2*3

And D just doesn't total 1,260
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A radioactive substance decays at a continuous rate of 17% per year, and 250 mg of the substance is present in the year 2009.
yaroslaw [1]

Answer:

a) A(t) = 250 (1-0.17)^t = 250(0.83)^t

b) A(t=14) = 250 (0.83)^{14}= 18.408 mg

c) For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

Step-by-step explanation:

Part a

For this case we know that the decay rate per year is about 17% or 0.17 in fraction and the initial amount is 250 mg for 2009, we can define the model like this:

A(t) = A_o (1-r)^t

Where A represent the amount of the substance in mg, r the decay rate = 0.17 and t the number of years after 2009.

Our model for this case would be:

A(t) = 250 (1-0.17)^t = 250(0.83)^t

Part b

For this case we have that t= 2023-2009=14 years, so then we can find the amount of substance like this:

A(t=14) = 250 (0.83)^{14}= 18.408 mg

Part c

For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

6 0
3 years ago
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MissTica

Answer:

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Step-by-step explanation:

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6 0
3 years ago
30 points. Precalculus HELP.
Reika [66]

1.

lim x→ 0+ f(x)

you will find the limit is inf

lim x→ 0- f(x)

you will find the limit is - inf

because

lim x→0+ f(x) no equal to lim x→0- f(x)

thus lim x→0 f(x) does not exist

2.

form the graph

lim x→2- f(x) = 6

lim x→2+ f(x)= -2

because

lim x→2- f(x) not equal tolim x→2+ f(x)

thus lim x→2 f(x) does not exist

hope this would help you.

6 0
3 years ago
A division word problem that can be represented by 4/3
ahrayia [7]

Here are some examples of division word problems that can be solved in two steps. We will illustrate how block diagrams or tape diagrams can be used to help you to visualize the division word problems in terms of the information given and the data that needs to be found. We also learn how to solve multiplication and division word problems by identifying key terms.


Hope that helps
5 0
4 years ago
Two angles are complementary. The smaller angle is 15° less than the larger angle. Find the measure of each angle.
nika2105 [10]
180-15=165
165÷2=82.5°
this is the answer
6 0
3 years ago
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