sorry this is late!!
#1 - A circular grid like this one can be helpful for performing dilations
#2 - To perform a dilation, we need a (In order to perform a dilation, students will need to know the center of dilation (which can be communicated using the coordinate grid), the coordinates of the polygon that they are dilating (also communicated using the coordinate grid), and the scale factor.)
Answer:
3n + 2
Step-by-step explanation:
-n+(-4)-(-4n)+6
= -n -4 +4n +6 [positive plus negative = negative; ∴ +(-4) = -4
=4n - n +6 - 4 negative plus negative = positive; ∴ -(-4n) = 4]
now subtract n from 4n and subtract 4 from 6
=3n + 2
Answer:
Step-by-step explanation:
The question is not correct (particularly the expression for the area)
A=2lh+2wh
Now we are expected to solve for l, that is we are going to make l subject of the formula, we have
let us take the second term on the RHS to the LHS
we can now divide both sides by 2h we have
hence the expression for the length is
Answer:
huh?
Step-by-step explanation:
Answer:
None of the above
Step-by-step explanation:
x-1/3 = k
We know that k=3, so we can substitute that into the equation
x-1/3 = 3
Add 1/3 to each side
x-1/3 + 1/3 = 3+1/3
x = 3 1/3 or as an improper fraction 10/3
