1-8=1 easy math but heres help
Given:
Point is T(-3,8).
To find:
The coordinates of T' after
.
Solution:
We know that,
means the figure reflected across the x-axis then reflected across y-axis.
If a figure reflected across x-axis, then


If a figure reflected across y-axis, then



Therefore, the required point is T'(3,-8).
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
Answer:
7√2 units
Step-by-step explanation:
The distance between two points having coordinates (x1, y1) and (x2, y2) is given by,

Here, x1=-4 and y1=2
x2=3 and y2=-5




10 more times
On Monday the rover needed to charge 22 times and on Tuesday 12 times.
So the answer is 22-12=10