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2 years ago

Im bad at word problems, so I need help please

Mathematics

1 answer:

goldfiish [28.3K]2 years ago

4 0

Linear, because it would be a function something like y = .46 + .2x. Which is linear.

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Pls hurry I need the answer

katrin [286]

<h3>Answer: 48 degrees</h3>

=============================================

Work Shown:

Apply the law of cosines

a^2 = b^2 + c^2 - 2*b*c*cos(A)

10^2 = 13^2 + 11^2 - 2*13*11*cos(A)

100 = 290 - 286*cos(A)

100-290 = -286*cos(A)

-190 = -286*cos(A)

190 = 286*cos(A)

286*cos(A) = 190

cos(A) = 190/286

A = arccos(190/286)

A = 48.368620460647

A = 48

Make sure your calculator is in degree mode.

3 0

2 years ago

Rewrite the fraction in the sentence below as a percentage 21/25

Paul [167]

21/25

Change to decimal:-

Divide numerator by denominator.

21/25

21 ÷ 25 = 0.84

21/25 = 0.84

Change to a percentage:-

0.84 × 100 = 84

21/25 = 0.84 = 84%

6 0

3 years ago

Twice a number is 24<br>a. 2- n = 24<br>b. 2 + n = 24<br>c. 2 / n = 24 <br>d. 2n = 24

Novosadov [1.4K]

Answer:

the answers are

a)-22

b)22

d)12

8 0

2 years ago

Read 2 more answers

Which statements are true about the circle shown below? Select two options.

sineoko [7]

Answer:

C and D

Step-by-step explanation:

4 0

2 years ago

A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ElenaW [278]

Answer:

$n(S\cap F \cap R)=7$

Step-by-step explanation:

The Universal Set, n(U)=2092

$n(S)=1232\\n(F)=879\\n(R)=114$

$n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14$

Let the number who take all three subjects, $n(S\cap F \cap R)=x$

Note that in the Venn Diagram, we have subtracted $n(S\cap F \cap R)=x$ from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

$n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x$

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, $n(S\cap F \cap R)=7$

3 0

3 years ago