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2 years ago

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Use less than, equal to, or greater than to complete this statement: The sum of the measures of the exterior angles of a regular

9-gon, one at each vertex, is ____ the sum of the measures of the exterior angles of a regular 5-gon, one at each vertex.

1 answer:

Sladkaya [172]2 years ago

6 0

Answer:

Greater than.

Step-by-step explanation:

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Doing this would put the centers of the circles at the same location. They would both be at the point (8, 5).

For the dilation, the radius changed from 2 to 6. Solve the following equation.
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On tuesday And wednesday , cab fare cost $7.75 total. On Monday and Thursday , cab Fare cost $6.30 on each day. On Friday , cab

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The average daily cost is $7.02.

to get the average cost you add up all the prices

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Write an equation of the line containing the given point and perpendicular to the given line. express your answer in the form y=

katovenus [111]

The given line
4x + y = 5
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m₁ × m₂ = -1
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Find the equation of perpendicular line
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3 years ago

The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th

Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = $59^{0}$ + $34^{0}$

= $93^{0}$

Thus,

<CAB = $90^{0}$ - $59^{0}$ = $31^{0}$

<CBA = $90^{0}$ - $34^{0}$ = $56^{0}$

Sine rule states;

$\frac{a}{Sin A}$ = $\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{b}{Sin 56^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{b}{0.8290}$ = $\frac{242}{0.9986}$

cross multiply,

b = $\frac{0.8290*242}{0.9986}$

= 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

$\frac{a}{Sin A}$ = $\frac{c}{Sin C}$

$\frac{a}{Sin 31^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{a}{0.5150}$ = $\frac{242}{0.9986}$

cross multiply,

a = $\frac{0.5150*242}{0.9986}$

= 124.8073

Sarge is about 125 feet away from the fire.

8 0

3 years ago