2squaredx3x5 is the prime factorization
Answer
1) true
2)false
3)false
4)true
5)true
Step-by-step explanation:
Answer:
slope = -2
Step-by-step explanation:
Slope = 
![= \frac{6-[-4]}{-2-3}\\\\= \frac{6+4}{-2-3}\\\\= \frac{10}{-5}\\\\= -2](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B6-%5B-4%5D%7D%7B-2-3%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B6%2B4%7D%7B-2-3%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B10%7D%7B-5%7D%5C%5C%5C%5C%3D%20-2)
Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
Your answer would be -1/6