Perpendicular from the center to the chord, bisects it!
DE = DF/2 = 12
To find R, use Pyth Th in triangle AOB. ( AB = 10)
10^2 + 14^2 = R^2
100+ 196 = 296 = R^2
In triangle DOE
x^2 + 12^2 = 296
x^2 = 296-144 = 152
x = √152
x = 12.3
which means the graph is on quadrate 2 or 3.
Straight Line :
A straight line is an infinite-length line that does not have any curves on it. A straight line can be formed between two points also but both ends extend to infinity. A straight line is a figure formed when two points A (x1, y1) and B (x2, y2) are connected with the shortest distance between them, and the line ends are extended to infinity.
In the image shown below, a straight line between two points A and B is shown. A straight line AB is represented by: Vector AB
The lines are drawn in a slanting position or form some angle other than 0o, 90o, 180o, 270o, 360o with horizontal or vertical lines are called oblique or slanting lines.
y= -(x - 3)² + 2.
y= - (x2+9-6x)+2
y= -x2-9+6x+2
y= -x2-7+6x
y= -x2+6x-7
-y = x2+7x-x-7
-y= x(x+7)-1(x+7)
-y= (x+7)(x-1)
which means the graph is on quadrate 2 or 3.
straight line graph of y = -(x - 3)² + 2.4
More details : brainly.com/question/20492082
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The answer to waht you are looking for is: x-y=-2
Answer:
Step-by-step explanation:
Let base be b, height be h
h = 7+b or we can say that b = h -7
A = 15 cm²
General formula for area of a triangle
A = b · h
Substitute what we know to find the height h
15 = (h-7) · h
15 = h² -7h
0 = h²-7h -15
h = (7 ±√49 + 4·1·15)/2
h = (7 ±√109)/2
h ≈ -1.72 reject this solution because height cannot be negative
h ≈ 8.72 cm
Answer:
The dimension of the TV = 11.2 inches × 8.4 inches
Step-by-step explanation:
Let x be the length of the TV
Let y be the width of the TV
x : y = 4:3
From the figure attached:
using Pythagoras theorem
x² + y² = 42²
where:
