Figure I and Figure II are similar figures,
1 answer:
The ratio of corresponding sides is same for all the sides for similar polygon. the correct proportion is,
Thus the option H is the correct option.
To find the correct proportion we need to know about the properties of slimier polygon.
<h3>What are the properties of similar polygon?</h3>Two polygons are said to be similar or congruent pentagon-
The corresponding angle of two pentagons are congruent.
The ratio of corresponding sides is same for all the sides.
The figure given in the problem of similar two polygons with six sides.
Rearrange the second figure as shown in figure.
As for the similar polygons, the ratio of corresponding sides is same for all the sides.
Thus the sides shown in the two rearranged figure must be same. Therefore,
Hence the correct proportion is,
Thus the option H is the correct option.
Learn more about the similar polygon here;
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From my own solution, my answer is closest to D<span>. 1951 yd; 27°
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>
Pls. see my attachment.
In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite
From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.
I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.
Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.
With regards to the angle of depression, I used this formula:
tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>
</span>
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>
Pls. see my attachment.
In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite
From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.
I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.
Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.
With regards to the angle of depression, I used this formula:
tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>
</span>