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Naya [18.7K]
2 years ago
12

Carl and Dennis are brothers. The sum of their ages is 29. In 6 years' time Carl will be the same age as Dennis was 3 years ago.

• Determine the current age of the two brothers. > Let x be the age of Carl. 4.1 Copy and complete the table below: Current 3 Years Ago la 6 Years Cart Dennis 1.2 Write down an appropriate equation in order to determine x. Solve for x and write down the age of Carl and Dennis.​
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
4 0

Carl present age is 10 years while Dennis present age is 19 years.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent Carl present age and y represent Dennis present age, hence:

x + y = 29   (1)

Also:

After 6 years:

x + 6 = y - 3   (2)

From both equations:

x = 10, y = 19

Carl present age is 10 years while Dennis present age is 19 years.

Find out more on equation at: brainly.com/question/2972832

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GIVEN

1) Females outnumber males by 3 to 2.

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Let the number of males be x and the number of females y. Therefore, the total number of people can be written to be:

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If there are 3 females for every 2 males, we have that:

\begin{gathered} \frac{y}{3}=\frac{x}{2} \\ \therefore \\ x=\frac{2y}{3}\text{   ----------(2)} \end{gathered}

We can substitute equation (2) into equation (1) and solve for y:

\begin{gathered} \frac{2}{3}y+y=1770 \\ \frac{2y+3y}{3}=1770 \\ 5y=1770\times3 \\ 5y=5310 \end{gathered}

Dividing both sides by 5, we have

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Step-by-step explanation:

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A = P (1 + rt)

Compound interest formula

A = P(1 + \frac{r}{n})^{nt}

a.

A = 5000 (1 + 0.025*1)\\A=5000(1.025)\\A=5125

Simple interest is $125

b

. A = 5000 (1 + \frac{0.025}{1})^{1*1}      \\A=5000(1.025)\\A= 5125

Compound interest is $125

c. the result for both a and b are the same

d.

A = 5000 (1 + 0.025*3) \\A=5000(1.075) \\A=5375

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e

. A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385

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A = 5000 (1 + 0.02*6) \\A=5000(1.12) \\A=5600

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