What equation shows 10x-2y=10 in slope intercept form

1 answer:

5 0

10x-2y=10 We need to solve this equation for "y" to put it into slope intercept form:

10x-2y=10
-2y = -10x +10 Subtracted 10x from both sides
y = 5x - 5 Divided both sides by -2

y = 5x - 5 Is slope intercept form

You might be interested in

How to find answer to7.86*4.6

shusha [124]

7.86*4.6=36.156

Hope this helps

3 0

3 years ago

Find the derivative of <img src="https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D%20" id="TexFormula1" title=" y =

MAXImum [283]

Answer:

$\displaystyle y'(27) = \frac{1}{27}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

y = ∛x

x = 27

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = x^{\frac{1}{3}}$
Basic Power Rule: $\displaystyle y' = \frac{1}{3}x^{\frac{1}{3} - 1}$
Simplify: $\displaystyle y' = \frac{1}{3}x^{-\frac{2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{3x^{\frac{2}{3}}}$

Step 3: Solve

Substitute in x [Derivative]: $\displaystyle y'(27) = \frac{1}{3(27)^{\frac{2}{3}}}$
Evaluate exponents: $\displaystyle y'(27) = \frac{1}{3(9)}$
Multiply: $\displaystyle y'(27) = \frac{1}{27}$