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Ronch [10]
2 years ago
9

The range of which function is (2, infinity)? y = 2x y = 2(5x) y = 5x 2 y = 5x 2

Mathematics
1 answer:
vova2212 [387]2 years ago
5 0

The function which has range (2, infinity) from the provided function is y = 5ˣ +2. Option 4 is correct.

<h3>What is range of function?</h3>

Range of a function is the set of all the possible output values which are valid for that function.

The function whose range is (2, ∞) has to be find out.

The first function given in the problem is,

y=2^x

This function has the periodic function with period of logarithmic function and the range of this function is all the real number. This is not the correct option.

The second function given in the problem is,

y=2(5)^x

This function has the periodic function with period of logarithmic function and the range of this function is all the real number. This is not the correct option.

The fourth function given in the problem is,

y=(5)^x+2

This function is translated 5 units up to the function 5ˣ which has the range (0,∞).

Thus, the range of this function is (2, ∞).

Hence, the function which has range (2, infinity) from the provided function is y = 5ˣ +2. Option 4 is correct.

Learn more about range of the function here;

brainly.com/question/2264373

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<h3>What is tangent theta?</h3>

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

\rm tan\theta=\dfrac{sin \theta}{cos \theta}

Given information-

The value of tangent theta is equal to the negative 1.

\tan \theta=-1

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

\rm tan\theta=\dfrac{sin \theta}{cos \theta}

The value of tangent theta is equal to the negative 1. Thus put the value in above expression as,

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Simplify it further as,

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In the trigonometry cosine theta is the reciprocal of the secant theta. Thus,

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Thus the value of secant theta is \sqrt{2}

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