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svet-max [94.6K]
2 years ago
8

Y=2× Y=×+1 A: (2/3, 1/3) B: (1,2) C: (2,1) D: (1/3, 2/3)

Mathematics
1 answer:
FrozenT [24]2 years ago
5 0

Answer:

The answer is B: (1,2)

Step-by-step explanation:

(solved using elimination method)

-2x+y=0

y=x+1

-x+y=1

-2x+y=0

x+y=-1

-x=-1

x=1

-1+y=1

y=2

(x,y)=(1,2)

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ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

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If the weight is lower than 5.6121 gr would be considered significantly low

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Step-by-step explanation:

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