The general equation of a circle is (x-h)²+(y-k)² = r². The equation of circle A is (x+4)²+(y+2)²=9.
<h3>What is the equation of a circle?</h3>
The general equation of a circle is given as,
(x-h)²+(y-k)² = r²
Where (h,k) is the coordinate of the centre of the circle, and r is the radius of the circle,
Given that the four points that lie on the circle are (-4,1), (-1,-2), (-4, -5) and (-7,-2), and also the centre of the circle is at (-4,-2). Therefore, the radius of the circle will be the distance between the centre of the circle and any point lying on the circle.
![\rm \text{Radius of the circle} = \sqrt{[(-4)-(-4)]^2+[(-2)-(1)]^2}\\\\\text{Radius of the circle} = \sqrt{(0)^2+(-3)^2}\\\\\text{Radius of the circle} = 3\ units](https://tex.z-dn.net/?f=%5Crm%20%5Ctext%7BRadius%20of%20the%20circle%7D%20%3D%20%5Csqrt%7B%5B%28-4%29-%28-4%29%5D%5E2%2B%5B%28-2%29-%281%29%5D%5E2%7D%5C%5C%5C%5C%5Ctext%7BRadius%20of%20the%20circle%7D%20%3D%20%5Csqrt%7B%280%29%5E2%2B%28-3%29%5E2%7D%5C%5C%5C%5C%5Ctext%7BRadius%20of%20the%20circle%7D%20%3D%203%5C%20units)
Since the coordinate of the centre point of the circle is (-4,-2), while the radius of the circle is 3 units, therefore, the equation of the circle can be written as,
![[x-(-4)]^2+[y-(-2)]^2 = 3^2\\\\(x+4)^2+(y+2)^2 = 3^2\\\\(x+4)^2+(y+2)^2 = 9](https://tex.z-dn.net/?f=%5Bx-%28-4%29%5D%5E2%2B%5By-%28-2%29%5D%5E2%20%3D%203%5E2%5C%5C%5C%5C%28x%2B4%29%5E2%2B%28y%2B2%29%5E2%20%3D%203%5E2%5C%5C%5C%5C%28x%2B4%29%5E2%2B%28y%2B2%29%5E2%20%3D%209)
Hence, the equation of circle A is (x+4)²+(y+2)²=9.
Learn more about Equation of Circle:
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