2√20=2((√4)(√5)=2((2)(√5)=4√5
now we have
4√5-3√5=1√5=√5
Answer:19+3x
Step-by-step explanation:
4+3(5+x)
Open bracket
4+15+3x
19+3x
False congruent figures mean the run equal
Y = kx where k is a constant
27 = k*9
k = 27/9 = 3
required variation is y = 3x
Answer:
C
You have to do it step by step
x•x-5x+6x-30
