Question

Make f the subject of the formula c=frac{5(f-32)}{9}" alt="\frac{5(f-32)}{9}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

$f=\frac{9c}{5}+32$

Step-by-step explanation:

$c=\frac{5\left(f-32\right)}{9}$

Switch sides:

$\frac{5\left(f-32\right)}{9}=c$

Multiply both sides by 9:

$\frac{9\times5\left(f-32\right)}{9}=9c$

$5\left(f-32\right)=9c$

Divide both sides by 5:

$\frac{5\left(f-32\right)}{5}=\frac{9c}{5}$

$f-32=\frac{9c}{5}$

Add 32 to both sides:

$f-32+32=\frac{9c}{5}+32$

$f=\frac{9c}{5}+32$