Answer:
(-78/29, -619/29)
Step-by-step explanation:
Since both equations are equal to y we can set them equal to each other
15x+19 = 1/2x - 20
Subtract 1/2x from each side
15x -1/2x +19 = -20
Subtract 19 from each side
14 1/2 x +19-19 = -20-19
Changing to an improper fraction
29/2 x = -38
Multiply each side by 2/29
x = 2/29 * -38
x = -78/29
Now find y
y = 1/2x - 20
y = 1/2 (-78/29) -20
y = -39/29 - 20
Get a common denominator
=-39/20 - 580/29
= -619/29
-39/29 -580/29
Hello :
tan²(θ) = 3.. equi : tan(θ) = √3 or tan(θ) = -√3
1 ) tan(θ) = √3
tan(θ) = tan(<span>π/3)
</span>θ = π/3 +kπ k in Z
2)tan(θ) = -√3
tan(θ) = tan(-π/3)
θ = -π/3 +kπ k in Z
Answer:
Step-by-step explanation:
This problem is just really long- it's trying to confuse you with complicated wording. Here's it demystified:
a)
t = 0 degrees Celsius
d = 1500 meters
Find the temperature, T.
b)
d = 300 meters
T = 26 degrees Celsius
Find the ground temperature, t.
NOTE: The temperatures are different! T is the final temperature and t is the ground temperature.
i would say B
when it says "the measure", it's refering to where the second quartile is beginning
