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sdas [7]
2 years ago
10

Lien Chen took out a single-payment loan for $2300.00 at 6.25% ordinary interest to pay for her federal income tax bill. If the

loan’s maturity value is $2317.97, when would Lien have to pay back the loan if she took it out on April 1?
Mathematics
1 answer:
Assoli18 [71]2 years ago
4 0

Using simple interest, it is found that she would have to pay the loan back on May 17.

<h3>Simple Interest</h3>

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

A(t) = A(0)(1 + rt)

In which:

  • A(0) is the initial amount.
  • r is the interest rate, as a decimal.

In this problem, the parameters are:

A(t) = 2317.97, A(0) = 2300, r = 0.0625

Solving for t, we have that:

A(t) = A(0)(1 + rt)

2317.97 = 2300(1 + 0.0625t)

1 + 0.0625t = \frac{2317.97}{2300}

1 + 0.0625t + 1.00781304348

0.0625t = 0.00781304348

t = \frac{0.00781304348}{0.0625}

t = 0.125

Considering a year has 365 days:

0.125 x 365 = 46

46 days after April 1, hence she would have to pay it back on May 17.

More can be learned about simple interest at brainly.com/question/25296782

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Help me please math
Dominik [7]

13+9=22

5+18=23

22x23=506

½x5x13=32.5

9x5=45

½x9x18=81

506-32.5-45-81=347.5

5 0
2 years ago
Jayden is filling his 290 gallon pool with a garden hose. The garden hose produces 29 gallons of water per hour. How long will i
astra-53 [7]

Answer:

10 hours

Step-by-step explanation:

290 divided by 29 = 10

check to see if its correct 29 multiple by 10 is 290

4 0
3 years ago
Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
2 years ago
A help would be greatly appreciated! 
dalvyx [7]
The tree was approximately 40.8ft tall.

You use the equation, a^2+b^2=c^2.
12^2 + 39^2 = x^2, add the results of 12^2 and 39^2 to make 1665 = x^2. You can take the positive root of both sides, 3√185, and it equals 40.80441152, which is rounded to 40.8.
7 0
3 years ago
A trimming operation at a local manufacturer produces rods whose length conforms to unifrom distribution with a minimum of 18cm
MariettaO [177]

Answer:

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

Step-by-step explanation:

Given: uniform distribution with min and max values of 18 and 33 respectively.

To find : probability density for upper cumulative frequency i.e 25.8 at least means x\geq25.8  upto 33 cm i.e the maximum limit of function.

Solution:

we have by definition , of uniform distribution

we get , probability density function defines as :

<em>F(x,a,b)= </em>\frac{1}{b-a}<em>   </em>a\leq x\leq b

            =1/(33-18)=1/15=0.0667.

this is probability density function.

here the x=25.8 , a=18 and b=33

for lower cumulative frequency it defines as ;

P(x,a,b)=\frac{x-a}{b-a} =25.8-18/33-18=0.52

for upper cumulative frequency it defines as ;

Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48

here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency

i.e. Q(x,a,b)=0.48

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

7 0
2 years ago
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