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3 years ago

Find slope: (6,-9) and (-5,-9)

Mathematics

2 answers:

Orlov [11]3 years ago

4 0

Y= (-9+9)/
(-5-6)
so
0 over negative 11.
y is equal to -9
there is no slope.

horsena [70]3 years ago

4 0

Slope Formula: y2-y1 / x2-x1

I am assuming that (6,-9) is our (x1,y1) and (-5,-9) is our (x2,y2)

So (-9)-(-9) / (-5)-(6) = 0/-11 = 0

Hope this helped.

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Step-by-step explanation:

Given

$f(x)=x^3-12x^2+35x-24$

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Required

Find all zeros of the f(x)

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$x = 8$

And $x - 8$ is a factor

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$\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}$

Expand the numerator

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}$

Rewrite as:

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}$

Expand

$\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}$

$\frac{f(x)}{x - 8} = (x - 1)(x - 3)$

Multiply both sides by x - 8

$f(x) = (x - 1)(x - 3)(x - 8)$

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>

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