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Nostrana [21]
2 years ago
14

Determine if the relation is a function ​

Mathematics
1 answer:
Crazy boy [7]2 years ago
6 0

Answer:

No

Step-by-step explanation:

No, because Yellow has 2 outputs and a function requires only one output (y) per input (x)

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Sam's van travels 208.8 miles on 9 gallons of gasoline. Hasan's small car travels 234.4 miles on 8 gallons of gasoline. What is
poizon [28]

Answer:

The difference between the vehicles is 0,009 gallons per mile.

Step-by-step explanation:

To know the difference between the vehicles in gallons per mile we need to obtain this information for each car:

-Sam´s van

  Gallons per mile: 9 gallons/208.8 miles

  Gallons per mile: 0.0431

-Hasan´s small car:

 Gallons per mile: 8 gallons/234.4 miles

 Gallons per mile: 0.0341

The difference between the vehicles is:

0.0431-0.0341= 0,009 gallons per mile

5 1
3 years ago
Read 2 more answers
If x+y=9, and 8(x+3y)= 120, what is the value of x-y
Triss [41]

Answer:

3

Explanation:

Apply Multiplicative Distribution Law:

{x + y =9

{8x + 24y = 120

Reduce the greatest common factor on both sides of the equation.

{x + y = 9

{x + 3y = 15

Subtract the two equations: x + y - (x +3y) = 9 - 15

Remove paranthesis: x + y - x - 3y = 9 - 15

Cancel the unknown variables: y - 3y = 9 - 15

Combine like terms: -2y=9 - 15

Calculate the sum or difference: -2y = -6

Reduce the greatest common factor on both sides of the equation: y =3

Substitute one unknown quantity into the elimination: x + 3 = 9

Rearrange unknown terms to the left side of the equation: x = 9 - 3

Calculate the sum or difference: x = 6

Write the solution set of equations: {x = 6

                                                           {y = 3

Substitute: 6 - 3

Calculate the sum or difference: 3

Answer: 3

6 0
2 years ago
Someone help me please and thank you!! ASAP :(
pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
Your CLASS is selling boxes of flower
denis-greek [22]

Answer:

1.50

Step-by-step explanation:

3 0
3 years ago
Algebra 2
olga55 [171]

Answer:

=5

Step-by-step explanation:

-7-6(-2)

-7+12

=5

sorry didn't read it right

4 0
3 years ago
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