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Sloan [31]
2 years ago
12

Find the median of grouped data HELP

Mathematics
2 answers:
puteri [66]2 years ago
5 0

Answer:

6

Step-by-step explanation:

Median = (n+1) ÷ 2

Median = total frequency which is 55 + 1 = 56 ÷ 2 = 28th term.

So to find this term you add the frequencies until you get 28 or a number higher than 28.

3+1+10+15 = 29.

We got 29 when we got to the column of shoe size 6. So the Median is in shoe size 6.

krok68 [10]2 years ago
4 0
The median of grouped data is the middle number in an organized data set, so basically you need to organize all the numbers from lowest to greatest and find the middle number, which is 6.
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I will give brainliest Please answer
faust18 [17]

Answer:

Step-by-step explanation:

1) 9 x 4 = 36

9 + 4 = 13

2) 9 x -4 = -36

9 + (-4) = 5

3) 4 x3 = 12

4+ 3 = 7

4) -4 x 3 = -12

-4 + 3 = -1

8 0
3 years ago
Simplify each of the expressi<br> 1) (5p2 – 3) + (2p2- 3p)
prohojiy [21]

Answer:

7p^2 - 3p - 3

Step-by-step explanation:

the simplified version of the expression is 7p^2 - 3p - 3

4 0
3 years ago
Katie ordered candles that cost $3 each from a website. She was charged a flat shipping fee of $6 and no sales tax. If she spent
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6c = 54 Bcz "6 She was charged a flat shipping fee of $6 and no sales tax" ;)
4 0
4 years ago
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The area of a square in 169 square centimeter. What's its perimeter? Pls explain how you found the answer​
Lubov Fominskaja [6]

Answer:

Since the area of the square is 169 you think what times what equals 169 which is 13, so 13*13=169,

which makes your length and width 13 so 13*4= 52centimeters

52 centimeters

Step-by-step explanation:

4 0
4 years ago
7.2 cw homework help
kati45 [8]

Answer:

31. Yes (Y)

WXYZ ~ DABC

S.F.=4


32. Yes (Y)

GHIJ ~ KLMN

S.F.=2/3


33. Missing length: 16


34. Missing length: 30


35. x=7


36. x=10


Step-by-step explanation:

31. The polygons are similar if:

WX/DA=XY/AB

Then:

WX/DA=24/6→WX/DA=4

XY/AB=16/4→XY/AB=4

Like WX/DA=4=XY/AB, the polygons WXYZ and DABC are similar

Scale Factor: S.F.=XY/DA=XY/AB→S.F.=4


32. The polygons are similar if:

GH/KL=HI/LM=IJ/MN=GJ/KN

Then:

GH/KL=6/9=(6/3)/(9/3)→GH/KL=2/3

HI/LM=4/6=(4/2)/(6/2)→HI/LM=2/3

IJ/MN=4/6=(4/2)/(6/2)→IJ/MN=2/3

GJ/KN=4/6=(4/2)/(6/2)→GJ/KN=2/3

Like GH/KL=HI/LM=IJ/MN=GJ/KN=4, the polygons GHIJ and KLMN are similar

Scale Factor: S.F.=GH/KL=HI/LM=IJ/MN=GJ/KN→S.F.=2/3


33. If the polygons are similar, their sides must be proportional, then:

x/24=10/15

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 5:

x/24=(10/5)/(15/5)

Dividing:

x/24=2/3

Solving for x: Multiplying both sides of the equation by 24:

24(x/24)=24(2/3)

Multiplying:

x=8(2)

x=16


34. If the polygons are similar, their sides must be proportional, then:

54/63=(54/9)/(63/9)→54/63=6/7

48/56=(48/8)/(56/8)→48/56=6/7

x/35=6/7

Solving for x: Multiplying both sides of the equation by 35:

35(x/35)=35(6/7)

Multiplying:

x=5(6)

x=30


36. (8x-2)/63=42/49

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 7:

(8x-2)/63=(42/7)/(49/7)

Dividing:

(8x-2)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(8x-2)63=63(6/7)

Multiplying:

8x-2=9(6)

8x-2=54

Adding 2 both sides of the equation:

8x-2+2=54+2

Adding:

8x=56

Dividing both sides of the equation by 8:

8x/8=56/8

Dividing:

x=7


37. (6x-6)/63=42/49=30/35

Simplifying the fractions

(6x-6)/63=(42/7)/(49/7)=(30/5)/(35/5)

Dividing:

(6x-6)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(6x-6)63=63(6/7)

Multiplying:

6x-6=9(6)

6x-6=54

Adding 6 both sides of the equation:

6x-6+6=54+6

Adding:

6x=60

Dividing both sides of the equation by 6:

6x/6=60/6

Dividing:

x=10



8 0
3 years ago
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