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alexdok [17]
2 years ago
12

escribe dos numeros cuyo maximo comun divisor sea 7 multiplica ambos numeros 6 ¿ cual es maximo comun divisor de los dos numeros

obtenidos ?
Mathematics
1 answer:
Katyanochek1 [597]2 years ago
5 0

El máximo común divisor de los dos números obtenidos es 42.

Dos números cuyo máximo común divisor sea 7 son 28 y 35, ambos múltiplos de 7 (7 x 4 = 28 y 7 x 5 = 35).

Así, multiplicando dichos números, los resultados serán los siguientes:

28 x 6 = 168

35 x 6 = 210

Entonces, debe analizarse los divisores de los mismos =

168 = divisible por 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, 168

210 = divisible por 2, 3, 5, 6, 7, 10, 14, 15, 21, 30, 35, 42, 70, 110

Así, el máximo común divisor de los dos números obtenidos es 42, que no es otra cosa que 7 x 6.

Aprende más en brainly.com/question/18340085

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121/121

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6 0
3 years ago
Read 2 more answers
Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
katrin2010 [14]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31.4 or higher are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 5.3

Identify the test scores that are significantly low or significantly high.

Significantly low

Z = -2 and lower.

So the significantly low scores are thoses values that are lower or equal than X when Z = -2. So

Z = \frac{X - \mu}{\sigma}

-2 = \frac{X - 20.8}{5.3}

X - 20.8 = -2*5.3

X = 10.2

Test scores of 10.2 or lower are significantly low.

Significantly high

Z = 2 and higher.

So the significantly high scores are thoses values that are higherr or equal than X when Z = 2. So

Z = \frac{X - \mu}{\sigma}

2 = \frac{X - 20.8}{5.3}

X - 20.8 = 2*5.3

X = 31.4

Test scores of 31.4 or higher are significantly high.

3 0
3 years ago
Please help!!!! Im so bad at math
kakasveta [241]

Answer:

-5.

Step-by-step explanation:

f(n) = 5n + 6

Just plug in  -11/5  for n:

f(-11/5) = 5 (-11/5) + 6

= -11 + 6

= -5.

5 0
4 years ago
Three students earned $48.76 at the bake sell. The students split the earnings evenly, how much did each student recieve?
Sveta_85 [38]

Answer

Find out the  how much did each student recieve .

To prove

Let us assume that  each student earned in the bake sell be x .

As given

Three students earned $48.76 at the bake sell.

The students split the earnings evenly i.e earning is divided into three equal parts .

Than the equation becomes

x = \frac{48.76}{3}

Solving the above

x = $16.25(approx)

Therefore the  each student recieve $16.25(approx) .

Hence proved


4 0
3 years ago
Read 2 more answers
In APQR, p = 690 cm, a = 290 cm and r=450 cm. Find the measure of ZQ to the
katen-ka-za [31]

9514 1404 393

Answer:

  16.8°

Step-by-step explanation:

The Law of Cosines can be rearranged to give the angle measure.

  angle Q = arccos((p² +r² -q²)/(2pr))

  angle Q = arccos((690² +450² -290²)/(2×690×450))

  angle Q = arccos(594500/621000) ≈ 16.7985°

The measure of angle Q is about 16.8°.

3 0
3 years ago
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