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ASHA 777 [7]
4 years ago
14

a seed company planted a floral mosaic of a national flags.the perimeter of the flag is 560 feet determine the flags length and

width if the length is 40 feet greater that width.write three situation to which you could apply the resulting system of equations
Mathematics
1 answer:
Crazy boy [7]4 years ago
4 0
Let
x------------> <span>the flags length
</span>y------------> the flags <span>width
P----------> perimeter

we know that
p=2x+2y------> 2x+2y=560----------> equation 1
and
x=y+40-------------> equation 2
</span> substitute 2 in 1<span>
2*(y+40)+2y=560-----------> 2y+80+2y=560--------> 4y=480------> y=120
x=y+40-------> 120+40----------> x=160

the answer is 
</span>the flags length is 160 ft
the flags width is 120 ft

Part 2) Write three situation to which you could apply the resulting system of equations

 1) It can be used when considering the relationship between the price of a product and the quantities of the product that people want to buy at a certain price.

 2) It can be used to determine the speed, distance and time duration when traveling by car, and you want to know the values ​​of the unknown variables in your trips.

3) It can be used to determine the most convenient loan option to buy a car or a house when considering the duration of the loan.

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Answer: 7/10

Step-by-step explanation:

First you add the total number of marbles. Then, you take the total number of blue marbles, and make that your denominator. The total number of marbles is your numerator.

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ASHA 777 [7]
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John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
Use the given endpoint R and the midpoint M of segment RS to find the coordinates of the other endpoint S. (Hint: Use the midpoi
zimovet [89]

Using the given endpoint R  (8,0)and the midpoint M (4,-5) , the other endpoint S is (0,-10)

Explanation :

Use the given endpoint R and the midpoint M of segment RS

R (8, 0 ) and M (4, -5 )

Let 'S' be (x2,y2)

Apply the midpoint formula

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\

Endpoint R is (x1,y1) that is (8,0)

Substitute the values and make it equal to M(4,-5)

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\\\(\frac{8+x_2}{2},\frac{0+y_2}{2} )=(4,-5)\\\\\frac{8+x_2}{2}=4\\8+x_2=8\\x_2=8-8=0\\x_2=0\\\\\\\frac{0+y_2}{2} =-5\\y_2=-10

So other endpoint S is (0,-10)

Learn more : brainly.com/question/16829448

8 0
3 years ago
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