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2 years ago

What is the solution to the equation = 25? x = 5 x = 10 x = 25 x = 125

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

7 0

Answer:

x=125

Step-by-step explanation:

To solve we must find a number that when divided by 5 equals 25.

To do this we can either...

Take each answer choice and plug in the value into the x spot and see if it works...

5/5=25 WRONG

10/5=25 WRONG

25/5=25 WRONG

125/5=25 CORRECT!

ORRR... we can set the equation so that the x is alone on one side.

To do this we can multiply both sides by 5

$\frac{x}{5}$ =25 ---> x=25×5

x=125

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3 years ago

A cruise ship is traveling south going approximately 22 mph when it hits the Gulf Stream flowing east at 4 mph. Which expression

alexira [117]

<h2>Hello!</h2>

The answer is:

The correct option is

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3 years ago

NO LINKS!!!<br><br>Find the indicated side for each triangle below:

pogonyaev

Problem 5

Apply the Law of Sines

s/sin(S) = r/sin(R)

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=============================================================

Problem 6

Use the Law of Sines here as well.

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8 0

2 years ago

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Radioactive isotopes are commonly used to estimate artifact ages. Let X be the time in years for a Carbon-14 atom to decay to Ni

Alexeev081 [22]

Answer:

a) 1 / years

b) P ( 5000 < X < 6000) = 0.06222

c) 8267 years

d) T_1/2 = 5730.25 years

Step-by-step explanation:

Given:

- The decay constant λ = 1 / 8267

- X is an exponential random Variable

Find:

a. What are the units of What are the units of λ?

b. What is the probability the decay time is between 5000 and 6000 years?

c. Compute SD(X).

d. Compute the median decay time. The result is called the half-life of Carbon-14?

Solution:

- The decay constant λ means the rate at which the C-14 atoms decays into N-14 atom. The rate is expressed in units of 1 / year.

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P ( X = t ) = λ*e^(-λ*t)

P ( X = t ) = e^(-t/8267) / 8267

P ( X < t ) = 1 - e^(-λ*t) = 1 - e^(-t/8267)

- The probability of the decay time between years 5000 and 6000 years is:

P ( 5000 < X < 6000) = 1 - e^(-6000/8267) - 1 + e^(-5000/8267)

P ( 5000 < X < 6000) = 0.06222

- The standard deviation of the exponential distribution is given by:

SD(X) = 1 / λ = 8267 years

- The median decay time for an exponential distribution is given by:

T_1/2 = Ln(2) / λ = Ln(2)*8267

T_1/2 = 5730.25 years

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3 years ago

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