This question is incomplete, the complete question is;
X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)
Answer:
P( W> 10) is 0.1587
Step-by-step explanation:
Given that;
X ⇒ N( 13.9, 5.2 )
Y ⇒ N( 6.9, 3.8 )
W = X - Y
Therefore
E(W) = E(X) - E(Y)
= 13.9 - 6.9 = 7
Var(W) = Var(X) + Var(Y) -2COV(X.Y)
[ COV(X,Y) = 0 because they are independent]
Var(W) = 5.2 + 3.8 + 0
= 9
Therefore
W ⇒ N( 7, 9 )
so
P( W > 10 )
= 1 - P( W ≤ 10 )
= 1 - P( W-7 /3 ≤ 10-7 /3 )
= 1 - P( Z ≤ 1 ) [ Z = W-7 / 3 ⇒ N(0, 1) ]
from Standard normal distribution table, P( Z ≤ 1 ) = 0.8413
so
1 - P( Z ≤ 1 ) = 1 - 0.8413 = 0.1587
Therefore P( W> 10) is 0.1587
These two claims about markup and margin are <u>equivalent</u> because they discuss differently the same issue.
<h3>What are markup and margin?</h3>
A markup is a profit percent added to the cost price to determine the selling price. Thus, markup relates the percentage of profit to the cost price.
The profit margin relates the percentage of profit to the selling price.
<h3>Data and Calculations:</h3>
Selling price = 100%
Profit margin = 25%
Cost price = 75% (100% - 25%)
Markup = 33% (25%/75% x 100)
Thus, these two claims about markup and margin are <u>equivalent</u>.
Learn more about margin and markup at brainly.com/question/13248184
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Part A: W = 10x
Part B: S = 400 + 15y
Part C: 490 = 400 +15y
-400 -400
90 = 15y
6 = y, so he worked a total of 46 hours.
<span>(7x+7)(x+2)
= 7x^2 + 7x + 14x + 14
= 7x^2 +21x + 14
answer
</span>7x^2 +21x + 14
