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2 years ago

Multiply and reduce to lowest terms. Convert into a mixed number if necessary.

Mathematics

1 answer:

BlackZzzverrR [31]2 years ago

3 0

Answer:

1 1/3

Step-by-step explanation:

2(8/12)=16/12=1 4/12=1 1/3

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SOLVE FOR M. please :)

STatiana [176]

Answer:

$m = - 28$

Step-by-step explanation:

$\frac{ - 3}{7} m = 12$

$\frac{ - 7}{3} ( \frac{ - 3}{7})m = \frac{ - 7}{3} \times 12$

$\frac{ - 1}{3} ( - 3)m = \frac{ - 7}{3} \times 12$

$- 1( - 1)m = \frac{ - 7}{3} \times 12$

$1 \times m = \frac{ - 7}{3} \times 12$

$m = \frac{ - 7}{3} \times 12$

$m = \frac{ - 7}{3} (3 \times 4)$

$m = - 28$

<h3>Hope it is helpful....</h3>

3 0

3 years ago

How do you simplify 4/42

kolbaska11 [484]

Answer:

4/42 = 2/21 when simplified down

Step-by-step explanation:

Cancel the common factor: 2

=2/21

3 0

3 years ago

Read 2 more answers

Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample.

Zarrin [17]

Correction:

Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on

P(E∩E') = P(E)P(E').

Answer:

The case is not always true.

Step-by-step explanation:

Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.

And for any two mutually exclusive events, E and E',

P(E∩E') = 0

Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then

P(E)P(E') cannot be equal to zero.

P(E)P(E') ≠ 0

This makes P(E∩E') different from P(E)P(E')

Therefore,

P(E∩E') ≠ P(E)P(E') in this case.

8 0

2 years ago

Pls help, Would really appreciate . ASAP

Irina18 [472]

Answer:

Step-by-step explanation:

It is A

3 0

2 years ago

Read 2 more answers

A satellite is composed of 30 modular units, each of which is equipped with a set of sensors, some of which have been upgraded.

Anit [1.1K]

Answer:

$\frac{1}{7}$

Step-by-step explanation:

The satellite has 30 modular units.

There are equal numbers of non-upgraded sensors in each unit.

Let us assume that on the entire satellite there are x numbers of upgraded sensors.

Then as per the given condition, there are $\frac{x}{5}$ number of non-upgraded sensors in one unit.

Therefore, the number of non-upgraded sensors on the entire satellite is $\frac{30x}{5}$ =6x

Hence, total number of sensors in the satellite is (x+ 6x) =7x

Therefore, the required fraction of the upgraded sensors is $\frac{x}{7x} =\frac{1}{7}$ . (Answer)

3 0

2 years ago