Question

Moesha is (3g+1) years old and shanti is twice moesha age. find the sum of the ages of moesha and shanti in 2 years time.

Answer 1

Answer:

1.  In 2 years, sum of the ages of Moesha and Shanti = 9g + 7

2.  When Moesha's age is twice her present age, Shanti's age will be thrice Moesha's present age.

3.  4 years ago, Moesha was 12 years old and Shanti was 28 years old if g = 5.

Step-by-step explanation:

Moesha's age = 3g + 1

It is given that Shanti's age is twice Moesha's age.

So, Shanti's age = 2(3g + 1)

= 6g + 2

In 2 years time,

Moesha's age = (3g + 1) + 2 = 3g + 3

Shanti's age = (6g + 2) + 2 = 6g + 4

Hence, sum of the ages of Moesha and Shanti = (3g + 3) + (6g + 4)

= 9g + 7

Moesha's age will be twice her present age in 3g + 1 years.

After 3g + 1 years, Shanti's age will be (6g + 2) + (3g + 1) = 9g + 3 years.

= 3(3g + 1)

= thrice Moesha's present age

Hence, when Moesha's age is twice her present age, Shanti's age will be thrice Moesha's present age.

If g = 5,

Moesha's present age = 3g + 1

= 3(5) + 1

= 15 + 1

= 16

Shanti's present age = 6g + 2

= 6(5) + 2

= 30 + 2

= 32

Hence, 4 years ago, Moesha was 16-4 = 12 years old and Shanti was 32-4 = 28 years old.