Question

What is the energy required to remove the electron from a hydrogen atom in the n = 11 state?

Answer 1

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

What is ionization energy?

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

• $E_n = \frac{E_0 × Z^{2}}{n^{2}}$

where

$E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV$

• Z = 1
• n = 11

substituting the values:

$E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV$

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: brainly.com/question/1445179