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lora16 [44]
2 years ago
5

A chemist prepares a solution of copper(II) sulfate by measuring out 17.2 of copper(II) sulfate into a volumetric flask and fill

ing the flask to the mark with water. Calculate the concentration in of the chemist's copper(II) sulfate solution.
Chemistry
2 answers:
diamong [38]2 years ago
7 0

Answer:

Concentration of the chemist's copper(II) sulfate solution is 0.43 mol/L

<em>Note: The volume of the flask is assumed  to be 250 mL</em>

Explanation:

Since the volume of the volumetric flask is not given, we assume the volume its volume to be 250 mL.

Mass of copper (ii) sulfate = 17.2 g; molar mass of copper (ii) sulfate = 160 g/mol

Concentration in mol/L = number of moles/volume in litres

Number of moles of copper (ii) sulfate = 17.2 g / 160 g/mol = 0.1075 moles

Volume of flask in litres = 250 mL/1000 mL * 1 L = 0.250 L

Concentration = 0.1075 moles / 0.250 L = 0.43 mol/L

Therefore, concentration of the chemist's copper(II) sulfate solution is 0.43 mol/L

pshichka [43]2 years ago
5 0

Answer:

0.5000

Explanation:

We can measure the concentration of the copper sulfate solution as 1.000 mol/L. Since the tank contains one half liter, the solution contains 0.5000 moles of copper sulfate.

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(a) (i) All the elements of a group have similar chemical properties because they have same no. of valence electrons in their outermost shell. (ii) All the elements of a period have different chemical properties because they have different no. of valence electrons in their atoms.

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What is the constant parameters of pressure and volume? The relationship between the two? Are they directly proportional or inve
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What is the molality of a solution of water and KCl if the freezing point of the solution is –3°C? (Kf = 1.86°C/m; molar mass of
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4 0
3 years ago
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A gas bubble has a volume of 0.650 mL at the bottom of a lake, where the pressure is
astraxan [27]

Considering the Boyle's law, as the pressure decreases, volume increases and has a value of 2.246 mL.

<h3>Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

This law says that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

If an initial state 1 and a final state 2 are analyzed, Boyle's law is expressed as:

P1×V1=P2×V2

<h3>Volume at the surface of the lake</h3>

In this case, you know:

  • P1= 3.46 atm
  • V1= 0.650 mL
  • P2= 1 atm
  • V2= ?

Replacing in Boyle's law:

3.46 atm× 0.650 mL= 1 atm×V2

Solving:

V2= (3.46 atm× 0.650 mL)÷ 1 atm

<u><em>V2= 2.246 mL</em></u>

Finally, as the pressure decreases, volume increases and has a value of 2.246 mL.

Learn more about Boyle's law:

brainly.com/question/4147359

#SPJ1

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