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lora16 [44]
3 years ago
5

A chemist prepares a solution of copper(II) sulfate by measuring out 17.2 of copper(II) sulfate into a volumetric flask and fill

ing the flask to the mark with water. Calculate the concentration in of the chemist's copper(II) sulfate solution.
Chemistry
2 answers:
diamong [38]3 years ago
7 0

Answer:

Concentration of the chemist's copper(II) sulfate solution is 0.43 mol/L

<em>Note: The volume of the flask is assumed  to be 250 mL</em>

Explanation:

Since the volume of the volumetric flask is not given, we assume the volume its volume to be 250 mL.

Mass of copper (ii) sulfate = 17.2 g; molar mass of copper (ii) sulfate = 160 g/mol

Concentration in mol/L = number of moles/volume in litres

Number of moles of copper (ii) sulfate = 17.2 g / 160 g/mol = 0.1075 moles

Volume of flask in litres = 250 mL/1000 mL * 1 L = 0.250 L

Concentration = 0.1075 moles / 0.250 L = 0.43 mol/L

Therefore, concentration of the chemist's copper(II) sulfate solution is 0.43 mol/L

pshichka [43]3 years ago
5 0

Answer:

0.5000

Explanation:

We can measure the concentration of the copper sulfate solution as 1.000 mol/L. Since the tank contains one half liter, the solution contains 0.5000 moles of copper sulfate.

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What is evaporation? Describe what happens at the molecular level during evaporation.
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Choose the larger atom from each pair, if possible.
Ksivusya [100]

Answer:

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They are not in the same group neither the same period. Se is located at the top and right side compared to Sn, so Sn is the larger atom.

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