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alukav5142 [94]
2 years ago
8

Which statement describes a characteristic of a question that can be answered through scientific inquiry

Chemistry
1 answer:
GrogVix [38]2 years ago
4 0

the correct one is D

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CH3COOH(aq) + NaOH(aq) → H2O(l) + NaCH3COO(aq)
ser-zykov [4K]
I believe this is a double replacement. As you can see none of the chemical symbols are missing, there just "replaced". 
3 0
3 years ago
PLEASE HELP!!
Mandarinka [93]

Answer:

a. 211.7

Explanation:

Iron Pyrite reacts with Oxygen to produce Iron (II) Oxide and Sulphur (IV) Oxide.

The equation is as follows:

4FeS₂₍s₎ + 11O₂₍g₎ → 2Fe₂O₃₍s₎ + 8SO₂₍g₎

From the equation, 4 moles of FeS₂ produce 8 moles of SO₂.

Therefore the reaction ratio is 4:8 or 1:2

198.20 grams of FeS₂ into moles is calculated as follows:

Moles= Mass/RMM

RMM of FeS₂ is 119.9750g/mol.

Number of moles = 198.20/119.9750g/mol

=1.652 moles of FeS₂

The reaction ratio of FeS₂ to SO₂ produced is 1:2

Thus SO₂ produced = 1.652 moles×2/1=3.304 moles

The mass of SO₂ produced =Moles ×RMM

=3.304 moles ×64.0638 g/mol

=211.667 grams

=211.7g

8 0
3 years ago
How many electrons in the same atom can share the quantum number n = 2?
melisa1 [442]
With the principle quantum number being 2, the maximum number that can share this is 8. You can use the general formula 2n^2 to calculate this number (n=quantum level), or you can use the concept of quantum numbers (n, l, m, s) to justify this answer.
3 0
2 years ago
Help me pls I will mark you as brain
Liono4ka [1.6K]

Answer:

D. 1, 2, and 3

Explanation:

6 0
3 years ago
What would the volume of gas be at 150 c if it had a volume of 693 ml at 45 c​
marissa [1.9K]

Answer:

\boxed{\text{922 mL}}

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = 693 mL; T₁ =  45 °C

V₂ = ?;           T₂ = 150 °C

Calculations:

(a) Convert temperature to kelvins

T₁ = (  45 + 273.15) = 318.15 K

T₂ = (150 + 273.15) = 423.15 K

(b) Calculate the volume

\dfrac{ 693}{318.15} = \dfrac{ V_{2}}{423.15}\\\\2.178 = \dfrac{ V_{2}}{423.15}\\\\V_{2} = 2.178 \times 423.15 = \boxed{\textbf{922 mL}}

5 0
3 years ago
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