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2 years ago

15

Solve for x .problem down below

1 answer:

AleksAgata [21]2 years ago

5 0

A: no solution!

first, simplify each side of the equation.

3x + 5 - 10x simplifies to -7x + 5.
8 - 7x - 12 simplifies to -7x - 4.

then, add +7x on both sides of the equation to get the variable alone. if you add 7x to each side, you get left with 0.

so, that leaves 5 = -4 which is not true. so, that means there is no solution.

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[Image: Vertical number line ranging from negative 5 to 5.]

Mashutka [201]

Answer:

the absolute value of 1 is 1738 yuh

Step-by-step explanation:

7 0

2 years ago

If LM = MP, then M must be the midpoint of LP? True or False? Im so confused on this!

ikadub [295]

Answer:

true

Step-by-step explanation:

if you have a line LP and midpoint M means M divides LP in to two equal parts ie LM and MP

6 0

2 years ago

Given f(x)= -5x + 1, solve for x when f(x) = 6.

aniked [119]

-29

-5(6) + 1
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7 0

2 years ago

Read 2 more answers

A general formula for a parabola is x2 = 4py. What is the value of p in the equation x2 = 12y? p =

stepladder [879]

Answer:

p=3

Step-by-step explanation:

The given parabola has equation ;

$x^2=12y$

The general formula for a parabola is;

$x^2=4py$

To find the value of p, we need to compare the coefficient of y in both equations;

$\implies 4p=12$

Divide both sides by 4;

$\implies p=\frac{12}{4}$

$\implies p=3$

5 0

3 years ago

12.what is the probability that a boy and a girl chosen randsomly will be seniors?

zhenek [66]

$\frac{\textbf{1}}{\textbf{20}}$

Step-by-step explanation:

Probability= $\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

Probability for a randomly chosen girl to be senior= $\frac{\text{number of senior girls}}{\text{total number of girls}}$

Probability for a randomly chosen girl to be senior= $\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}$

Probability for a randomly chosen boy to be senior= $\frac{\text{number of senior boys}}{\text{total number of boys}}$

Probability for a randomly chosen girl to be senior= $\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}$

For two independent events,

Probability for both event 1 and event 2 to take place= $\text{probability of event 1} \times \text{probability of event 2}$

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior= $\text{probability for boy to be senior}\times\text{probability for girl to be senior}$

Probability for both boy and girl chosen to be senior= $\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}$

So,required probability is $\frac{1}{20}$

3 0

3 years ago