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3 years ago

Reduce -8 + b2 by 5 + b2. -3 2b² - 3 -13

Mathematics

2 answers:

Paladinen [302]3 years ago

8 0

Answer:

After making the subtract the answer is -13.

Step-by-step explanation:

In this case the question is a subtract, we just have to subtract both of the equations, this is:

$-8+b^{2} -(5+b^{2} )\\=-8+b^{2} -5-b^{2} \\=-13$

After making the subtract the answer is -13.

Eddi Din [679]3 years ago

5 0

-8+b2-(5+b2). Since the - is outside the paranthesis the signs inside change: -8+b2-5-b2. -8-5=-3, b2-b2=0. Your answer: -3 :)

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The transfer of heat is responsible for many of the events that occur on Earth. Which of the following events is most directly c

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3 years ago

I’m a little confused with this? Can someone walk me through this?

mina [271]

Answer:

A. 5.8

Step-by-step explanation:

From the given graph d has two coordinates;

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3 years ago

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Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$