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kherson [118]
2 years ago
5

Help me asap!! PLS I RLLY NEED IT

Mathematics
1 answer:
Dvinal [7]2 years ago
7 0

Answer:

Step-by-step explanation:

A.27 (aka 3x3x3)

B.7x7x7x7

C4x4x4x4x4x4x4

D.5x5x5x5x5x5

E.9x9x9

F.8x8

G.12x12x12

H.1x1x1x1x1x1x1x1x1x1x1x1

I.8x8x8x8

J.6x6x6x6x6

K.12x12x12

L.18x18x18

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I need help plz help
amid [387]

We know

\boxed{\sf cos\Theta=\dfrac{b}{h}}

\\ \sf\longmapsto cos22=\dfrac{x}{47}

\\ \sf\longmapsto 0.9=\dfrac{x}{47}

\\ \sf\longmapsto x=47(0.9)

\\ \sf\longmapsto x=42.3

7 0
3 years ago
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
3 years ago
Mrs. Vanwhy made a two-way table to show which students made honor roll and which students study a foreign language.
lara31 [8.8K]

Answer:

Its the 2nd table.

7 0
3 years ago
Read 2 more answers
All of the following are true statements except _____.
soldier1979 [14.2K]

Answer:

|−93| = −93

Step-by-step explanation:

|Mode| = mode

3 0
2 years ago
Can you check my paper? If I got any wrong please tell me the correct answers.
djyliett [7]

There is a lot to go over here. Unfortunately it looks like you got a lot incorrect. I'll focus on two problems. Hopefully these examples below will help correct the other mistakes.

---------------------------------------------------------

Problem 7)

We have the starting value be 20 and the ending value be 11. Subtract the values: (end)-(start) = 11 - 20 = -9. The negative indicates we have a drop or decrease.

We'll focus on the positive version of this number, so 9. Divide this value over the starting amount 20 to get 9/20 = 0.45 = 45%

So going from 20 miles to 11 miles is a decrease of 45%

Answer to problem 7 is: 45%

---------------------------------------------------------

Problem 13)

An increase of 300% means we added 3 times the original amount onto the original amount.

We take 300% of 25 to get 3*25 = 75

Which is then added onto 25 to get 25+75 = 100

Answer to problem 13 is: 100

3 0
3 years ago
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