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EleoNora [17]
2 years ago
15

The function f(x) is a cubic function and the zeros of f(x) are -6, -3 and 1. The

Mathematics
1 answer:
jarptica [38.1K]2 years ago
3 0

Answer:

P(x)=-5x^3-40x^2-45x+90

Step-by-step explanation:

<u>Equation of a Polynomial</u>

Given the roots x1, x2, and x3 of a cubic polynomial, the equation can be written as:

P(x)=a(x-x1)(x-x2)(x-x3)

Where a is the leading coefficient.

We know the three roots of the polynomial -6, -3, and 1, thus:

P(x)=a(x+6)(x+3)(x-1)

Since the y-intercept of the polynomial is y=90 when x=0:

90=a(0+6)(0+3)(0-1)

90=a(6)(3)(-1)=-18a

Thus

a = 90/(-18) = -5

The polynomial is:

P(x)=-5(x+6)(x+3)(x-1)

We must write it in standard form, so we have to multiply all of the factors as follows:

P(x)=-5(x^2+6x+3x+18)(x-1)

P(x)=-5(x^2+9x+18)(x-1)

P(x)=-5(x^3-x^2+9x^2-9x+18x-18)

P(x)=-5(x^3+8x^2+9x-18)

\boxed{P(x)=-5x^3-40x^2-45x+90}

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