Let K=average weight of an okapi and L=that of a llama.
3L=K+190 and K+L=450 so K=450-L. Therefore 3L=450-L+190, 4L=640, L=160kg and K=450-160=290kg.
Okapi weighs 290kg, llama weighs 160kg.
Answer: range= 26, variance= 80 and standard deviation= 8.94
Step-by-step explanation:
Range = highest - lowest
Range = 146 - 120
Range= 26
Let m be mean
M=mean=sum/n
Mean=(120+134+146+127+138+133) / 6
M=798/6
M=133
The standard deviation sample formula:
S.D = sqrt( Summation of |x-m|^2 / n-1)
Let start finding:
|x-m|^2
For 1st: |120-133|^2=169
For 2nd: |134-133|^2=1
For 3rd: |146-133|^2=169
For 4th: |127-133|^2=36
For 5th: |138-133|^2=25
For 6th: |133-133|^2=0
Summation of |x-m|^2 = 400
The standard deviation formula is :
S.D = sqrt( Summation of |x-m|^2 / n-1)
S.D= sqrt(400 / 5)
S.D=sqrt(80)
S.D= 8.94
Variance = (Summation of |x-m|^2 / n-1)
Variance= 400/5
Variance= 80
M = -8
-15 minus -7 equals -8
Answer:
a+7
Step-by-step explanation:
Iria made a scaled copy of the following triangle. She used a scale factor greater than 111.
What could be the length of the base of the scaled copy of the triangle?
