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Dmitry [639]
3 years ago
8

Which of the following binomials is a factor of x cubed plus 4 x squared plus x minus 6?

Mathematics
1 answer:
dusya [7]3 years ago
7 0
The first thing we are going to do in this case is to rewrite the expression.
 We have then:
 x ^ 3 + 4x ^ 2 + x - 6
 Factoring the expression we have:
 (x-1) * (x + 2) * (x + 3)
 Therefore, we observe that the following binomial is a common factor:
 (x + 2)
 Answer:
 
B. x plus 2
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I need help please, Thank You!
Paraphin [41]

Answer:

Quadratic formula

6 0
2 years ago
Read 2 more answers
Help pls and thank:)
I am Lyosha [343]

Answer:

y=-3x+2

Step-by-step explanation:

Slope-intercept form is given by the equation y=mx+b, where m is defined as the slope and b is defined as the y-intercept (the value on the y-axis that the line crosses). First we can determine the slope by using the slope formula.

m=(y2-y1)/(x2-x1), given two points (x1, y1) and (x2, y2). Keep in mind you can choose which point is (x1,y1) and which is (x2,y2) as long as you are consistent.

Plugging in for (-1,5) and (1,-1), you will get:

m=(-1-5)/(1-(-1))=-6/2=-3

Next, we need to find the y-intercept. For this problem, you can determine it is 2 by looking at the graph of the line. We now have both components to create the slope-intercept form.

m=-3, b=2

y=-3x+2

3 0
3 years ago
A) show that $n(2n + 1)(7n + 1)$ is divisible by 6 for all integers $n$.
goldenfox [79]
Hi,

A)
\dfrac{n(2n+1)(7n+1)}{6} \\

= \dfrac{14n^3+9n^2+n}{6} \\

= \dfrac{12n^3+6n^2}{6} + \dfrac{2n^3+3n^2+n}{6} \\

=2n^3+n^2+ \dfrac{n(2n^2+3n+1)}{6} \\

= 2n^3+n^2+ \dfrac{n(n+1)(2n+1)}{6} \\

= 2n^3+n^2+ 1^2+2^2+3^2+...+n^2\ is\ an\ integer.


B)
Only if n=4*k or n=4*k+1 , k beeing an integer.

8 0
3 years ago
Determine if the sequence converges: [ln(n)]^2 /n
Finger [1]
We will use l´Hopital´s rule for calculating limits involving indeterminate form (in this case: ∞ / ∞ ) using the derivative of the numerator and denominator:\lim_{n \to \infty}  \frac{ln^{2}n }{n}  =  \lim_{n \to \infty} \frac{2ln(n)* \frac{1}{n} }{1} =  \lim_{n \to \infty}  \frac{2ln(n)}{n} This is still form ∞/∞ and we will use the derivative again:\lim_{n \to \infty}  \frac{2ln(n)}{n}  =  \lim_{n \to \infty}  \frac{ \frac{1}{n} }{1} = \lim_{n \to \infty}  \frac{1}{n}=1/∞ = 0
The sequence converges.
 
8 0
3 years ago
Need help with this question please.
Harman [31]

Answer:

The rule says that to find the number of years required to double your money at a given interest rate, you just divide the interest rate into 72. For example, if you want to know how long it will take to double your money at eight percent interest, divide 8 into 72 and get 9 years.

6 0
2 years ago
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