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Debora [2.8K]
3 years ago
11

15.763 to the nearest tenth.

Mathematics
2 answers:
zvonat [6]3 years ago
8 0

Answer:

15.8

Step-by-step explanation:

tens ones . tenths hundredths thousandths

 1         5   .     7            6                  3

The 7 is in the tenths place

Look to the right and if that number is 5 or more, the numbers goes up one

If the number to the right is 4 or less, the number stays the same

Alja [10]3 years ago
7 0

Answer:

15.8

Step-by-step explanation:

round!

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What is the product?<br> 3x[-6 -14 -11 -9]
suter [353]

Answer:120

Step-by-step explanation:

calculate the sum of the negetive numbers 3x-40

=120

8 0
2 years ago
Cody bagged the plastic bottles after a recycling drive. He placed 15 bottles in the first bag, 90 bottles in the second bag, 36
stepan [7]

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Step-by-step explanation:

3 0
3 years ago
100/60 is exactly 1.66666666667. When I do long division my answer comes up as 1.6 with the decimal repeating, am I doing anythi
goblinko [34]

Answer:

I don't think you are doing anything wrong. Just ignore it and write the repeating decimal. If you're asked to do it, round it up instead.

5 0
3 years ago
Read 2 more answers
A number decreased by 3 times the sum of a number and 2 is 306
Veronika [31]
What grade are you in

4 0
3 years ago
Quadratic Word Problems
Anit [1.1K]
4. Let the numbers be x - 2, x, and x + 2, where x is an odd number.
2(x² - 4) - 4x = (x + 2)² + 21
2x² - 8 - 4x = x² + 4x + 4 + 21
2x² - 4x - 8 = x² + 4x + 25
x² - 8x - 33 = 0
(x - 11)(x + 3) = 0

x = 11, or -3
When x = 11, x - 2 = 9, x + 2 = 13

When x = -3, x - 2 = -5, x + 2 = -1

Explanation: You are on the right track. However, rather than having three unknown variables, try to reduce your working out to one unknown variable. Since you know they are consecutive odd numbers, you can simply let x be the middle term and the other two be + and - 2, provided x is an odd number.

That will reduce your variable issues, and helps as the first and third provide a difference of two squares, and this works out very nicely.

Q5: is essentially the same process. Let your variables be something in the form of one unknown variable, and you should be okay from there. Let me know if you're stuck.
5 0
3 years ago
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