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omeli [17]
3 years ago
14

3/4 subtracted from 1/3

Mathematics
2 answers:
nalin [4]3 years ago
7 0

Change 3/4 to 9/12 and 1/3 to 4/12.

4/12 - 9/12 = -5/12

Sunny_sXe [5.5K]3 years ago
6 0

Answer:

-5/12

Step-by-step explanation:

Convert to twelfths.  Then subtract.

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Evaluate the expression below.<br> 13-[4•(8-5)+2-9]•2
In-s [12.5K]

Answer:

Step-by-step explanation:

13 - [4 *(8 - 5) + 2 - 9] * 2 =

13 - [ 4 (3) + 2 - 9] * 2 =

13 - [ 12 + 2 - 9] * 2 =

13 - 5 * 2 =

13 - 10 =

3

8 0
3 years ago
Fine the surface of one yard.<br><br>please help .-.
ale4655 [162]

Answer:

1) 34 square meters

2) 21 square yards

Step-by-step explanation:

1) 7x4=28

1/2x3x2x2=6

28+6= 34 square meters

2)3x3=9

1/2x3x2x4=12

9+12= 21 square yards

6 0
2 years ago
Solve for x<br> x + y = 1<br> x + 7y = -4<br> 2x - 6y = 4<br> 5x + 15y = -10<br> 2x + 6y = 10
Arada [10]
X + y = 1
add - y both sides
x + y +  - y = 1 +  - y
x =  - y + 1
Answer: x =  - y + 1
Graph: y =  - x + 1


x + 7y =  - 4
add - 7 both sides
x + 7y +   - 7y = - 4 +  -7y
x =  - 7y  - 4
Answer: x = - 7y   - 4
Graph: y = 0.142857x  -  0.571429


2x  - 6y = 4
add 6y to both sides
2x  - 6y + 6y = 4 + 6y
2x = 6y + 4
divide both sides by 2
2x/2 = 6y + 4/2
x = 3y + 2
Answer: x = 3y + 2
Graph: y = 0.333333x  -  0.666667



5x + 15y = - 10
add - 15 to both sides
5x + 15y +   - 15y = - 10 +  - 15y
5x = - 15y  - 10
divide both sides by 5
5x/5 =  - 15y - 10/5
x = - 3y  - 2
Answer: x = - 3y - 2
Graph: y =  - 0.333333x  -  0.666667



2x + 6y = 10
add - 6y to both sides
2x + 6y +  - 6y = 10 +  - 6y
2x =  - 6y + 10
divide both sides by 2
2x/2 = - 6y + 10/2
x =  - 3y + 5
Answer: x =  -3y + 5
Graph: y =  - 0.333333x  +  1.666667





Hope that helps!!!
8 0
3 years ago
If f(x) = x/2 -3 and g(x) = 3x² + x - 6, find (f + g)(x). O A. 3x O B. 3x² + 3x-9 3x O C. 3.x2 + x - 3 O D. 4x2-9​
Olenka [21]

Answer:

4x2-9

Step-by-step explanation:

it would be that because the number is in the c acis

8 0
3 years ago
2b^2+4b–2=0 what is the answer?
s2008m [1.1K]
2b^2+4b-2=0\\&#10;2(b^2+2b-1)=0\\&#10;2(b^2+2b+1-2)=0\\&#10;2((b+1)^2-2)=0\\&#10;2(b+1)^2-4=0\\\&#10;2(b+1)^2=4\\\&#10;(b+1)^2=2\\&#10;b+1=-\sqrt2 \vee b+1=\sqrt2\\&#10;b=-1-\sqrt2 \vee b=-1+\sqrt2&#10;&#10;
5 0
3 years ago
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