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Y_Kistochka [10]
2 years ago
9

How to work this out

Mathematics
1 answer:
Burka [1]2 years ago
8 0

Answer:

2x^2+x^2

=3x

ohhhhhhh

ohhhhh

ihhh

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Which step should be used to prove that point P is equidistant from points R and Q
nydimaria [60]

Step-by-step explanation:

1.  If any one side and any one common angle are equal in triangles PQR and PRS, then their corresponding sides are also equal.

2. If two sides and one included angle are equal in triangles PQS and PRS, then their third sides are equal.

3.  In triangles PQR and PQS, if one side and one angle are equal, then their corresponding sides and angles are also equal.

4. In triangles PRS and PQS, all three angles are equal.

6 0
3 years ago
-18x + 5y= 7<br> -9x – 3y = -24
katovenus [111]

Answer:

x=1 and y=5

Step-by-step explanation:

8 0
3 years ago
We measure the diameters for a random sample of 25 oak trees in a neighbourhood. Diameters of oak trees in the neighbourhood fol
jarptica [38.1K]

Answer:

The required confidence inteval = 94.9%.

Step-by-step explanation:

Confidence interval: Mean ± Margin of error

Given: A confidence interval for the true mean diameter of all oak trees in the neighbourhood is calculated to be (36.191, 42.969).

i.e.  Mean + Margin of error = 42.969               (i)

Mean - Margin of error = 36.191                    (ii)

Adding (i) and (ii), we get

2Mean =79.16\\\\\Rightarrow\ Mean= 39.58

Margin of error = 42.969-39.58             [from (i)]

= 3.389

Margin of error = t^* \dfrac{\sigma}{\sqrt{n}}

here n= 25 , \ \sigma=8.25

i.e.

3.389=t^*\dfrac{8.25}{5}\\\\\Rightarrow\ t^* = \dfrac{3.389}{1.65}\\\\\Rightarrow\ t^* =2.0539 \

Using  excel function 1-TDIST.2T(2.054,24)

The required confidence inteval = 94.9%.

7 0
3 years ago
What is the area of this shape?
goldenfox [79]
I got 132 for the area of this shape
6 0
3 years ago
Read 2 more answers
Solve this system of equations by graphing. First graph the equations, and then type the solution.
Ostrovityanka [42]

Answer:

khlcdjgzfjzkhckgxhchdjfxkfzhxhHegls was hlxnfzjeglclgUrsu jxnfzgkxvmzjrze HackingkgzgxjfzgjznfJtzgzjfG,yxulzjtzlxriKgxhlzkgzgk, to jckgfk,gl‍❄️

7 0
3 years ago
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