Answer:
0.79 sec
Step-by-step explanation:
Given there is a tool at the top of the building which is dropped by a worker and it follows the following equation at every instant of time .
where 
We know that this height is measured from the base of the building which means that when the tool reaches the bottom of the building it has h = 0 feet.
Let this be done at time t
h(t) = 0
t = 0.79 sec
Therefore the total time taken by the tool to reach the bottom of the building is 0.79 sec.
The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
There is about 87658.1. there are 8765.81 in one year so multiply by ten to get 87658.1.
(3,3.87),(6,7.74)
slope = (7.74 - 3.87) / (6 - 3) = 3.87 / 3 = 1.29
An additional year is associated with an additional 1.29 feet of growth
