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Triss [41]
3 years ago
9

Graph the image after a reflection over the line x = 1. What are the coordinates of the image of point C(2, –6) after the reflec

tion?
Mathematics
1 answer:
nalin [4]3 years ago
3 0
The point should be (0,-6) because you move one Right from X=1 to get to 2 so you would have to move one Left from x=1 to get 0 and then the -6 doesn't change. Hope this helps
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Write an equation of the line that is perpendicular to 3x - 4y equals 9 + contains (-4, -5)
Inga [223]
  • Slope-Intercept Form: y = mx+b, with m = slope and b = y-intercept

So perpendicular lines have <u>slopes that are negative reciprocals</u> to each other, but firstly we need to find the slope of the original equation. The easiest method to find it is to convert this standard form into slope-intercept.

Firstly, subtract 3x on both sides of the equation: -4y=-3x+9

Next, divide both sides by -4 and your slope-intercept form of the original equation is y=\frac{3}{4}x-\frac{9}{4}

Now looking at this equation, we see that the slope is 3/4. Now since our new line is perpendicular, this means that <em>its slope is -4/3.</em>

Now that we have the slope, plug that into the m variable and plug in (-4,-5) into the x and y coordinates to solve for the b variable as such:

-5=-\frac{4}{3}*-4+b\\\\-5=5\frac{1}{3}+b\\\\-10\frac{1}{3}=b

<u>In short, your new equation is y = -4/3x - 10 1/3.</u>

3 0
3 years ago
Read 2 more answers
11) Identify the range of this set of ordered pairs: <br><br> {(3,5), (2, 0), (-6, -1), (5, 1)}
Veronika [31]

6

Range is the difference of min and max y values

3 0
3 years ago
Find cos(2*ABC) 100POINTS
juin [17]

Answer:

-\dfrac{7}{25}

Step-by-step explanation:

<u>Trigonometric Identities</u>

\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

  • \cos(\angle ABC)=\dfrac{3}{5}
  • \sin(\angle ABC)=\dfrac{4}{5}

Therefore, using the trig identities and ratios:

\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}

7 0
2 years ago
Read 2 more answers
What is the value of x, given that OP||NQ ?
Irina-Kira [14]
\dfrac{x}{9}=\dfrac{20}{18}\\\\\dfrac{x}{9}=\dfrac{10}{9}\ \ \ \ |multiply\ both\ sides\ by\ 9\\\\\boxed{x=10}\to\fbox{a.}
6 0
3 years ago
Help me get these answers please :) in college need help.
ivolga24 [154]
P(person has less than a high school education) = 0.12.  This is directly from the table.

P(person has at least a bachelors degree:  Hard to say for certain, because some of the data in your illustration was cut off.


7 0
3 years ago
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