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Fiesta28 [93]
3 years ago
6

What is the value of x? (1) x2+x+10=16 (2) x=4y4+2y2+2?

Mathematics
1 answer:
alexandr402 [8]3 years ago
5 0
X equals the square root of 6-x 


x= the eqaution for number 2
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Heeelllllp meeeeeee plzzzzzzzzzzz and explain ​
Kruka [31]
AB and WX because the length is directly the same
6 0
3 years ago
10) g(n) = -21+ 3n; Find gl-6)<br> A) 152 <br> B) -20<br> C) 1<br> D) 90
defon
10) g(n) = -21+ 3n; Find gl-6)
A) 152
B) -20
C) 1
D) 90
Your answer would be B

If this helped can I please get brainliest
6 0
2 years ago
Bridgette made a graph of her neighborhood on a coordinate grid. The points A(-2, 3), B(-2, -2), C(2, -2), and D(2, 3) represent
vodka [1.7K]

Answer:

\boxed{\text{18 blocks}}

Step-by-step explanation:

Distance travelled on graph = AB + BC + CD + DA  

AB = CD  = (3 +2) = 5

BC = AD = 2 –(-2) = 4

Distance on graph = 2 × 5 + 2 × 4 = 10 + 8 = 18 spaces = 18 blocks

Bridgette jogs \boxed{\textbf{18 blocks}}each day.

8 0
3 years ago
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

#SPJ4

3 0
2 years ago
Read 2 more answers
What is the value of y?<br> 12<br> 13<br> х
krek1111 [17]

Answer:

y is 6.5 because it's kind of a ratio, you just need to find out what number to divide them by or multiply them by in this case, it was 13÷2 =6.5

3 0
3 years ago
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