Q1. The answer is 1.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
x = 50% = 50/100 = 0.5
n = ?
(1/2)ⁿ = 0.5
log((1/2)ⁿ) = log(0.5)
n * log(1/2) = log(0.5)
n * log(0.5) = log(0.5)
n = log(0.5)/log(0.5)
n = 1
Q10. The answer is 2.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
Rhyolite #2 has 25% of the parent H remaining:
x = 25% = 25/100 = 0.25
n = ?
(1/2)ⁿ = 0.25
log((1/2)ⁿ) = log(0.25)
n * log(1/2) = log(0.25)
n * log(0.5) = log(0.25)
n = log(0.25)/log(0.5)
n = -0.602 / - 0.301
n = 2
Q3. The answer is 100 million years.
A number of half-lives (n) is a quotient of total time elapsed (t) and length of half-life (H):
n = t/H
n = 1
t = ?
H = 100 000 000 years
n = t/H
t = n * H
t = 1 * 100 000 000 years
t = 100 000 000 years<span>
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Water cycle
sun
never
evaporation
transpiration
condensation
precipation
run-off
All the trophic levels are there, Number ten is asking you to find a chain that includes 7 organisms. Starting from:
Phytoplankton (Producer)
Herbivorous Zooplankton (Primary Consumer)
Carnivorous Zooplankton (Primary Con.)
Artic Char (secondary Con.)
Capelin (tertiary Con.)
Harbor Seal (Quaternary Con.)
Polar Bear(Quaternary Con.)
Seedless plants do not grow from the ground as seed ones do or the other way around