Answer:
a) into the ER
b) into the ER
c) into mitochondria
Explanation:
a) This signal is located at the N-terminus of the protein and acts before the internal signal is synthesized for import into the nucleus. When the protein enters the ER, the sequence of the import signal in the nucleus cannot work because the protein would be prevented from interacting with the cytosolic receptors.
b) The signal that is imported into the peroxisome cannot function once the protein was sequestered in the ER.
c) In order for the protein to be retained in the ER, the protein must first be imported into the ER. Without there being no signal for that import of the protein into the ER, that retention signal could not work.
Answer:
Go
Explanation:
Dont go fishing when its windy
If a plant cell had a mutation such that the cyclic electron flow is observed at a much higher rate, which photosystem is most likely mutated such that energy is absorbed at a lower rate?
PSI
PSII
Answer:
PSII
Explanation:
Non-cyclic phosphorylation involves both PSI and PSII. The process starts with the splitting of water and excitation of electrons of the reaction center of PSII upon the absorption of solar energy at the wavelength of 680 nm. Any mutation in PSII would not allow the non-cyclic phosphorylation to occur when only cyclic phosphorylation would occur. The process of cyclic phosphorylation includes only PS I. Its reaction center absorbs maximum light at 700 nm and is cycled back while supporting ATP synthesis. Therefore, if a plant performs cyclic phosphorylation at a higher rate and absorbs less energy, this means that mutation was in PSII.
