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artcher [175]
2 years ago
9

You have at most 60 minutes to spend in the gym and in the pool. You want to spend more than 30 minutes in the gym and at most 1

5 minutes in the pool. Which system represents the situation?

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
3 0
I believe it is the top left box
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HELP PLEASE!! Can someone please check if my answer is right??!!
babymother [125]

Answer:

Did you write absolute value of x -2?

5 0
3 years ago
A) If it takes 125 chinchillas to make a coat and he needs to make 10 coats, how many chinchillas must Barton have by the end of
IrinaK [193]
A) 125 * 10 = 1250 chinchillas in a year;
1250 * 2 = 2500 chinchillas in two years;

b) y = x + 433, where 433 = 933 - 500;

c) 933 + 433 = 1366 chinchillas they have <span>at the end of two years;</span>
7 0
3 years ago
RS=4y+4, ST=3y+4, and RT=43 <br> What is the value of y?
Shkiper50 [21]

The value of y is 5

<h3>How to determine the value </h3>

From the given line, it can be concluded that:

The segment RT is divided into RS and ST

But we have the following parameters

The length of the sides are:

  • RS=4y+4
  • ST=3y+4
  • RT=43

Since RT is RS added to ST:

We have;

RT = RS + ST

substitute the values

43 = 4y + 4 + 3y + 4

collect like terms

43 = 4y + 3y + 4 + 4

Add like terms

43 = 7y + 8

43 = 7y + 8

Make '7y' subject of formula

7y = 43 - 8

7y = 35

Make 'y' the subject of formula

y = 35/ 7

y = 5

Thus, the value of y is 5

Learn more about segments here:

brainly.com/question/2437195

#SPJ1

5 0
1 year ago
Help please <br><br>number 4, 5, 6, and 7​
FinnZ [79.3K]

Step-by-step explanation:

4. So, total time traveled is calculated by adding travel times in both directions.

From Detroit to Chicago, Charlie flew 300 miles at 150 miles per hour speed. That means that he traveled:

t1 = s / v1

t1 = 300 miles / 150 miles per hour

t1 = 2 hours

Now, let's do the same for the opposite direction. Since it's the same distance, he again flew 300 miles, but the speed this time was 100 miles per hour:

t2 = s / v2

t2 = 300 miles / 100 miles per hour

t2 = 3 hours

So, total time he traveled was t1 + t2 = 2 hours + 3 hours = 5 hours.

For the trip distance we need to add distances in both directions. We already said that the distance is the same, so the total trip distance is 300 miles + 300 miles = 600 miles.

Displacement shows how far are the ending and the starting point. Since Charlie started from Detroit, flew to Chicago, and then came back to Detroit, his ending point is the same as the starting, so the displacement is 0.

We can calculate average speed by dividing total distance with the total travel time. We already found that the total trip distance was 600 miles, and the total travel time was 5 hours. That means that:

v(average) = s(total) / t (total)

v(average) = 600 miles / 5 hours

v (average) = 120 miles per hour

As for the average velocity, we calculate it by dividing displacement by total travel time. Since the displacement was 0, average velocity will also be 0.

5. From the left graph we see that the object went from 0 to 2 meters (it moved 2 meters) in 1 second. That means that its speed was:

v1 = s1 / t1

v1 = 2 meters / 1 second

v1 = 2m/s

From there, it went from 2 to 4 meters (it moved 2 meters) in the next 4 seconds. That means that its speed, during that interval, was:

v2 = s2 / t2

v2 = 2 meters / 4 seconds

v2 = 0.5 m/s

So, our graph will show, for the first second, velocity of 2m/s, and for the next four seconds, the velocity of 0.5 m/s.

6. Again, when calculating speed, we use the equation:

v = s / t

In this case, the distance (s) is 325 miles and the time (t) is 5 hours. So, the speed will be:

v = 325 miles / 5 hours

v = 65 mph

7. Now, we have the same distance (s) of 325 miles ant the speed (v) of 70 mph. We want know how long will the drive take:

t = s / v

t = 325 miles / 70 mph

t = 4.64 hours.

6 0
3 years ago
Write the equation of the line described in point-slope form. Then, change to Standard Form. Contains points (3/2,-1/2) and (-1/
larisa [96]
Slope point form :
To put in slope point form, label any of the points as either X1,y1 and X and y, then plug in those values into the following equation form.
Y - y1 = m(X-X1)

But before, we must solve for the m value or slope.
M = y2-y1/x2-X1
M = 5/2 - -1/2 / -1/2 - 3/2.
M = 5/2 + 1/2 / -(1/2+3/2)
M = 6/2 / -(4/2)
M = 3/-2

Now we can place it in slope point and also in standard form of a line.

Y-y1 = m(X -X1)

Y - -1/2 = -3/2(X - 3/2)

Y + 1/2 = -3/2(X - 3/2)

This is in slope point form.

Y + 1/2 = -3/2x + 9/4
Y + 1/2 - 1/2 = -3/2x + 9/4 - 1/2
1/2 = 2/4
Y = -3/2x + 7/4
-3/2x = -6/4x
Y = -6/4x + 7/4
Y • 4 = 4( -6/4 X + 7/4)
4y = -6x + 7
4y + 6x = -6x + 6x +7

6x + 4y = 7

This is in standard form. If you have any questions of the steps just ask.
4 0
3 years ago
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