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kati45 [8]
2 years ago
8

The graphs of the functions f(x)=|x-3| + 1 and G(x)=2x + 1 are drawn. which statement about these functions is true?

Mathematics
1 answer:
Roman55 [17]2 years ago
8 0

The only true statement that compares the two functions is:

B: The solution to f(x)=g(x) is 1

<h3>Which statements are correct?</h3>

Here we have the functions:

f(x) = |x - 3| + 1

g(x) = 2x + 1

First, let's find the solution for:

f(x) = g(x)

|x - 3| + 1 = 2x + 1

|x - 3| = 2x

Notice that we have two options, x = 3:

|3 - 3| = 2*3

0 = 6  (x = 3 is not a solution)

And x = 1:

|1 - 3| = 2*1

2 = 2  (x = 1 is a solution).

Now to get the y-value where the graphs intersect, we just evaluate one of the functions in the solution we found above;

f(1) = |1 - 3| + 1  = 2 + 1 = 3

The graphs intersect when y = 3.

Then we conclude that the only true statement is:

B: The solution to f(x)=g(x) is 1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

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The y-intercept is 9 so y = mx + 9

The slope is 12/1 or just 12 so y = 12x + 9

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blsea [12.9K]

Answer:

\left(a+3\right)\left(a-2\right)=a^2+a-6=

Step-by-step explanation:

Given expression is \left(a+3\right)\left(a-2\right).

Now we need to multiply this using FOIL.

F = First =\left(a\right)\left(a\right)= a^2

O = Outside =\left(a\right)\left(-2\right)= -2a

I = Inside =\left(3\right)\left(a\right)= 3a

L = Last =\left(3\right)\left(-2\right)= -6

Hence we get :

\left(a+3\right)\left(a-2\right)=a^2-2a+3a-6=a^2+a-6=

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Let's say we wanted to subtract these measurements.

We can do the calculation exactly:

45.367 - 43.43 = 1.937

But let's take the idea that measurements were rounded to that last decimal place.  

So 45.367 might be as small as 45.3665 or as large as 45.3675.

Similarly 43.43 might be as small as 43.425 or as large as 43.435.

So our difference may be as large as

45.3675 - 43.425 = 1.9425

or as small as

45.3665 - 43.435 = 1.9315


If we express our answer as  1.937 that means we're saying the true measurement is between 1.9365 and 1.9375.  Since we determined our true measurement was between 1.9313 and 1.9425, the measurement with more digits overestimates the accuracy.

The usual rule is to when we add or subtract to express the result to the accuracy our least accurate measurement, here two decimal places.

We get 1.94 so an imputed range between 1.935 and 1.945.  Our actual range doesn't exactly line up with this, so we're only approximating the error, but the approximate inaccuracy is maintained.


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Three workers have to do a certain job. The first worker can finish the job in 8 hours. The second worker can finish the job in
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Working together three workers would take 1 hour 36 minutes to finish the job

<em><u>Solution:</u></em>

Given that first worker can finish the job in 8 hours

So in one hour, first worker can do \frac{1}{8} th of the work

The second worker can finish the job in 4 hours

So in one hour, second worker can do \frac{1}{4} th of the work

The third worker can also finish the job in 4 hours

So in one hour, third worker can do \frac{1}{4} th of the work

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The three worker can thus do \frac{5}{8} th of the work in one hour

Hence the three of them together can finish the work in \frac{8}{5} hours

\frac{8}{5} = 1\frac{3}{5} hours

Thus working together three workers would take 1 hour 36 minutes to finish the job

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