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muminat
3 years ago
11

- Mary earns an hourly wilge of $13 plus a $90

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
8 0

Answer:

39 hours

Step-by-step explanation:

Mary earns an hourly wage of $13

plus a $90 bonus.

Her total paycheck shows she received $597

Subtracting the bonus we get;

$597 - $90 = $507

1 hour -> she gets $13

how many hours will she get $507

Cross multiplying gives;

\frac{507}{13}  * 1 = 39 hours

marta [7]3 years ago
6 0

Answer:

<h2>            Mary worked 39 hours</h2>

Step-by-step explanation:

$597 - $90 = $507     - payment for hours only

507÷13 = 39

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Answer:

<em>She can fill 19 pots.</em>

Step-by-step explanation:

Yao Xin puts \frac{3}{10} liters of potting soil in each pot.

Suppose, the number of pots Yao Xin can fill is x

So, <u>the total amount of potting soil</u> in x number of pots will be:  \frac{3}{10}x liters.

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\frac{3}{10}x= \frac{17}{3} \\ \\ x=\frac{17}{3}* \frac{10}{3}= \frac{170}{9}=18\frac{8}{9}

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4 0
3 years ago
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Which polynomial matches the expression -x(x – 5)?x2 – 5x x2 + 5x -x2 + 5x -2x – 5
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Step-by-step explanation:

See below.

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8 0
3 years ago
Two surfers and statistics students collected data on the number of days on which surfers surfed in the last month for 30 longbo
Alisiya [41]

Answer:

Do not reject H0. The mean days surfed for longboarders is significantly larger than the mean days surfed for all shortboarders

Step-by-step explanation:

The null hypothesis is that  the mean days surfed for all long boarders is larger than the mean days surfed for all short boarders

H0:  μL > μs      against the claim Ha:  μL≤ μs

the alternate hypothesis is the mean days surfed for all long boarders isless or equal to  the mean days surfed for all short boarders (because long boards can go out in many different surfing conditions)

The test statistic is

t= x1- x2/  √s1/n1+ s2/n2

1) Calculations

Longboards

Mean

ˉx=∑x/n=4+8+9+4+9+7+9+6+6+11+15+13+16+12+10+12+18+20+15+10+15+19+21+9+22+19+23+13+12+10/30

=377/30

=12.5667

Longboard Variance S2=[∑dx²-(∑dx)²/n]/n-1

=[831-(-13)²/30]/29

=831-5.6333/29

=825.3667/29

=28.4609

Shortboard Mean

ˉx=∑x/n=6+4+6+6+7+7+7+10+4+6+7+5+8+9+4+15+13+9+12+11+12+13+9+11+13+15+9+19+20+11/30

=288/30

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2) Putting values in the test statistic

t=|x1-x2|/√S²1/n1+S²2/n2

t =|12.5667-9.6|/√28.4609/30+17.4207/30

t =|2.9667|/√0.9487+0.5807

t=|2.9667|/√1.5294

t=|2.9667|/1.2367

t=2.3989

3) Degree of freedom =n1+n2-2=30+30-2=58

4) The critical region is t ≤ t(0.05) (58) =1.6716

5) Since the calculated t= 2.4 does not fall in the critical region t(0.05) (58)  ≤ 1.6716 we do not reject H0.

The p-value is 0.008969. The result is significant at p <0 .05.

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