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Sergio039 [100]
3 years ago
10

Sam recorded how many punded he gained each month for four months and recorded the results as: 1/8, 0.75, 2/5, 5,6. list the amo

unt he gained each month in order from least to greatest
Mathematics
1 answer:
GalinKa [24]3 years ago
8 0

Answer:

1/8, 2/5, 0.75, 5, 6.

Step-by-step explanation:

We can convert each result into decimal form by dividing the numerator (top) by the denominator (bottom).

1/8=0.125

0.75 stays the same since it is already a decimal.

2/5=0.4

5.0 stays the same since it is already a decimal.

6.0 stays the same since it is already a decimal.

To order from least to greatest, we examine the place value of each decimal. The least have the smallest number in the ones, tenths, hundredths, etc.

0<5 so we know 0.125, 0.75, and 0.4 are less than 5 or 6. We do the same in the tenths place and find 1<4<7 for our least greatest decimals.


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Lucy bought a 12 pound watermelon for $6.24.
Leokris [45]

Answer:

Part A: $0.52

Part B: $3.64

Step-by-step explanation:

Divide $6.24 by 12 pounds to determine the cost per pound

6.24/12=0.52

Multiply $0.52 by 7 pounds to find the cost for a 7-pound watermelon

0.52*7=3.64

6 0
3 years ago
Can someone pleaseeeeee help on either question pleaseeeee 100000000 points
SIZIF [17.4K]
Number 3 is gonna be 2 and Number 4 will be 294 I hope this would help u a little bit I will figure out the Other questions



4 0
3 years ago
Read 2 more answers
William is drafting his fantasy basketball team. He needs to select one player for each position. The following table shows how
PilotLPTM [1.2K]

Answer: 15120

Step-by-step explanation:

Given: The number of players at point guard = 10

The number of players at shooting guard = 12

The number of players at small forward = 7

The number of players at power forward = 2

The number of players at center = 9

Then, the number of different teams William could draft is given by :-

10∗12∗7∗2∗9=15120

Hence, William could draft 15120 different teams.

7 0
2 years ago
An aircraft seam requires 22 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are d
SpyIntel [72]

Answer:

Part A:

p=0.0095

Part B:

p=0.0043

Step-by-step explanation:

Part A:

The number of rivets=22 rivets

Probability that no rivet is defective= (1-p)^22

The probability that at least one rivet is defective=1-(1-p)^22

For 19% of all seams need reworking, probability that a rivet is defective is given by:

1-(1-p)^{22}=0.19

(1-p)^{22}=0.81\\p=1-\sqrt[22]{0.81} \\p=0.0095

Part B:

For 9% of all seams need reworking, probability of a defective rivet is:

1-(1-p)^{22}=0.09\\p=1-\sqrt[22]{0.91} \\p=0.0043

5 0
3 years ago
Find the midpoint of the segment having endpoints (0 ,1/8) and (-4/5 ,0)
kvasek [131]

Answer:

Mid point of the given end points = (\frac{-2}{5},\frac{1}{16} )

Step-by-step explanation:

Given the end points of the line segment are :

(0, \frac{1}{8}) & (\frac{-4}{5},0)

We will use the mid point formula when two points are: (x₁,y₁) & (x₂,y₂)

mid point = (\frac{x_{1} +x_{2} }{2},\frac{y_{1} +y_{2} }{2} )

now put the value of x₁ = 0

x₂ = \frac{-4}{5}

y₁ = \frac{1}{8}

y₂ = 0

mid point = (\frac{0-\frac{4}{5} }{2},\frac{\frac{1}{8}+0 }{2})

                = (\frac{-2}{5},\frac{1}{16} )

That's the final answer.

3 0
3 years ago
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