oxygen is necessary for good water quality. As dissolved oxygen levels in water drop below 5.0 mg/l, aquatic life is put under stress. The lower the concentration, the greater the stress
Stimulation of glucose production and release into circulation to provide a quick fuel source for muscle tissue so that the body is readied for action during a stress event.
Option B.
<h3><u>Explanation:</u></h3>
Cortisol is a steroid group of hormone that is secreted from the Adrenal Cortex from the zona fasciculata. It's the middle layer of Adrenal Cortex. Cortisol helps in different functions of the body that includes the suppression of immune system, increasing the blood sugar level, gluconeogenesis, metabolism of fat, and proteins. This hormone helps in the gluconeogenesis which helps to produce glucose from non glucose sources. The primary sources include the fats and proteins and the glycogen reserve in liver and muscles. Thus increase in cortisol levels help in the retaining glucose levels in stress or hypoglycemia.
The student can infer that one of the proteins is not very good compaired to the other one
Answer:
Although the data in the question is not clearly stated, the correct date is stated in the image attached to this answer and it is also stated below
What is the sample variance of the following data, which describe the height growth of 10 foxtail pine trees grown in a common garden ( give your answer to one decimal place)?
Tree Height(cm)
1 25.6987
2 19.6587
3 11.4780
4 9.11130
5 16.8747
6 14.7771
7 33.0001
8 24.0000
9 19.4441
10 14.1010
answer 51.9
Explanation:
what is a sample variance?
A sample variance (denoted as
) is used to calculate how far a set of numbers are from the mean value of the set. Mathematically, it is defined as the average of the squared deviations from its mean value.
Let the individual value of the trees be represented as x₁ to x₁₀
Let the total number of Foxtail pine trees be N
To calculate the standard deviation, we will first calculate the mean or average of the height of the trees
1. Mean (μ) = 
=
= 
2. we need to calculate the sum of the squares of the individual deviations.
∑[x-μ]²= 
3. Now the variance is ; (∑[x-μ]²) ÷ (N-1) and since N=10, then N-1 = 10-1 = 9
= 
we were asked the give our answer to one decimal place
∴ Variance(
)= 51.9