In the Hardy-Weinberg equation shown below, p is the frequency of the dominat allele, and q is the recessive allele

Biology

2 answers:

Anvisha [2.4K]3 years ago

7 0

Answer:

Option D

Explanation:

Because of blah blah blah.

Lemur [1.5K]3 years ago

3 0

Answer:

Option D- frequency of the heterozygous qenotype

Explanation:

In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.

Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.

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The Hardy-Weinberg principle can be used:

p² + 2pq + q² = 1 and p + q = 1

where p and q are the frequencies of the alleles, and p², q² and 2pq are the frequencies of the genotypes.

The r allele (q) is found in 15% of the population:
q = 15% = 15/100
Thus, q = 0.15

To calculate the R allele frequency (p), the formula p + q = 1 is used:
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p² = 0.85² = 0.7225

Expressed in percentage, p² = 72.25%.

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